Only 1 and 23.
23 and 29 are both prime numbers.
Oh, dude, let me break it down for you. So, first, you find how many numbers are divisible by 6, which is 166. Then you find how many are divisible by 21, which is 47. But wait, don't forget to subtract the ones divisible by both 6 and 21, which is 7. So, the total is 166 + 47 - 7 = 206 integers that fit the bill. Easy peasy!
1, 2, 5, 10, 23, 46, 115, 230
The Prime Numbers in the 20's are 23 and 29 because they are only divisible by 1 and the number itself.
Only 1 and 23.
Hence the last digits of both 23 and twenty 29 are divisible by three, the whole number is divisible by three, so the highest common factor of both 23 an 29 the answer is 3.
46 is divisible by these numbers: 1, 2, 23 and 46.
276 is a multiple of 12 that is divisible by 23.
Yes. 276 is divisible by these numbers: 1 2 3 4 6 12 23 46 69 92 138 and 276.
621 is divisible by these numbers: 1, 3, 9, 23, 27, 69, 207, 621.
Any of its multiples including itself
They are members of the infinite set of numbers of the form 23*k where k is an integer. Since the set is infinite, it is not possible to list them.
Yes, 46/90 can be simplified. Both 46 and 90 are divisible by 2, so we can divide both numbers by 2. This gives us 23/45. They share no common factors, so 23/45 is already in its simplest form.
It is: 1 is their HCF
345 is divisible by: 1 3 5 15 23 69 115 and 345.
69 is divisible by these numbers: 1, 3, 23, 69.