They are both divisible by 1 and 3
Yes. 207 is evenly divisible by 23.
No. It doesn't end in a 5 or 0.
Greatest common factor of a and b is a if b is divisible by a.Here, 69 is divisible by 23 therefore GCF is 23.
They are both divisible by: 14, 7, 2 and 1
NO, lets take an example.. 24 is divided by 2 and 8 both.. but not by 16..
Hence the last digits of both 23 and twenty 29 are divisible by three, the whole number is divisible by three, so the highest common factor of both 23 an 29 the answer is 3.
Any multiple of 276.
The GCF of 16 and 48 is 16 because both numbers are divisible by 16.
Only 1 and 23.
Yes, the GCF of a # doesn't have to be either of the 2 #'s. In the case of 16 and 42 the GCF is 2 because that is the greatest # that both the numbers are equally divisible by. If it was 16 and 48, then the GCF would be 16 because that is the highest # both are equally divisible by.
The smallest whole number divisible by both 8 and 12 is 24.
23 is a prime number so it is not divisible by 3. It is only divisible by 1 and 23. Dividing 23 by three gives the result of 7.6r
No. 23 is not divisible by anything except itself and one.
The numbers 16 and 20 are both multiples of 4. This means that both 16 and 20 can be divided evenly by 4 without leaving a remainder. In mathematical terms, we can say that both 16 and 20 are divisible by 4.
8, 4, 12, 16, etc.
8/9 They are both divisible by 2