It is: 1 is their HCF
They are both divisible by 1 and 3
No. It doesn't end in a 5 or 0.
Yes. 207 is evenly divisible by 23.
Greatest common factor of a and b is a if b is divisible by a.Here, 69 is divisible by 23 therefore GCF is 23.
They are both divisible by: 14, 7, 2 and 1
NO, lets take an example.. 24 is divided by 2 and 8 both.. but not by 16..
Hence the last digits of both 23 and twenty 29 are divisible by three, the whole number is divisible by three, so the highest common factor of both 23 an 29 the answer is 3.
Any multiple of 276.
The GCF of 16 and 48 is 16 because both numbers are divisible by 16.
Only 1 and 23.
A number between 200 and 300 that is divisible by both 23 and 5 is 230. This is because 230 is the product of 23 and 10, and both 23 and 5 are factors of 230. Additionally, it falls within the specified range.
The smallest whole number divisible by both 8 and 12 is 24.
23 is a prime number so it is not divisible by 3. It is only divisible by 1 and 23. Dividing 23 by three gives the result of 7.6r
No. 23 is not divisible by anything except itself and one.
No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.No. Both are divisible by 5.
No, both are divisible by 2.No, both are divisible by 2.No, both are divisible by 2.No, both are divisible by 2.
8, 4, 12, 16, etc.