use the FOIL system First, Outside, Inside, Last. when you see this (x -2)(5x -7) multiply the numbers that appear first in each system. in this case x and 5x. When multiplying variables simply raise the power. x times 5x = 5x^2. Then you multiply the two outside numbers in this case x and -7. which equals -7x. Then the inside numbers in the same manner. -2 and 5x equals -10x. and then the numbers that appear last in each system. -7 and -2 which equals +14. Finally add all the terms. 5x^2 + -10x + -7x + 14 = 5x^2 -17x +14
The factors of x2 are x and x.
You sure can, here is an example I made up to show you: x4+x2= x2(x2+x) When you factor it out it should look like this because if you multiply it back up (where the exponents will multiply not add) it will equal the primary equation.
x2 - 5x + 6 = (x - 2)(x - 3)
x2+9x-36 = (x-3)(x+12) when factored
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
The factors of x2 - x - 20 are (x - 5) and (x + 4) because when you multiply them together, they come out to x2 - x - 20.
-x2(5x5 + 13)
Multiply it, adah 5X7= 35
The factors of x2 are x and x.
5
The factors of x2 are x and x x times x plus 1 = x2 + x
First, I'll multiply by -1, to make it a little easier to work with (then when done, I'll multiply by -1 again): x2 + 2x - 48. We want two numbers, when multiplied yield -48, and the sum is 2: -6 and 8. (x + 8)(x - 6) works. Now multiply one of the binomial factors by -1: (x + 8)(6 - x). Multiply using FOIL to check: -x2 - 2x + 48
(5x600) + (5x7)= 3035 3000 + 35 = 3035
5x7 paper is commonly referred to as "5x7 size" or "5x7 inches."
Restate the question: Factor the polynomial x2 + 7x + 10. You look for two numbers which multiply to make 10 and add to make 7. They are 5 and 2. Now put them into the two factors: (x + 5)(x + 2). Check your factors by multiplying using 'FOIL': x2 + 2x + 5x + 10 = x2 + 7x + 10. Check!
x2 - 13 + 30 = x2 + 17, which has no real factors.
Multiply x2, then do it again.