3+2i + 6-4i = 9-2i
The real part of this number is positive, therefore it lies in Q1 or Q4.
The imaginary part is negative, therefore it is in Q3 or Q4.
Q4 is the common possibility, therefore 9-2i is in Q4.
3-2j.
A number of the form (a + bi) is a complex number.
Not exactly. The numbers (a & b) can be any real number (positive or negative). It is the letter i, which represents the imaginary unit sqrt(-1).False
The conjugate is 7-5i
-5 - 7i
It would be in the IV quadrant
Yes, the complex numbers, as well as the real numbers which are a subset of the complex numbers, form groups under addition.
no its real numbers
I don’t know
3-2j.
The concept of conjugate is usually used in complex numbers. If your complex number is a + bi, then its conjugate is a - bi.
1x plus 4y produces a 3 dimensional cuboid when it is graphed.
Yes, a+bi is standard form for a complex number. The numbers (a) and (b) are both real and i is √(-1)
That expression can't actually be factored without using complex numbers. If you want to use complex numbers, then it would come out as a "difference of squares":(x + i)(x - i)
The whole of the Real numbers, or even the whole of the complex plane.
a2 + b2 cannot be factorised in real numbers, only in complex numbers. The fact that you ask this question indicates that you are nowhere near old enough to be studying complex numbers.a2 + b2 cannot be factorised in real numbers, only in complex numbers. The fact that you ask this question indicates that you are nowhere near old enough to be studying complex numbers.a2 + b2 cannot be factorised in real numbers, only in complex numbers. The fact that you ask this question indicates that you are nowhere near old enough to be studying complex numbers.a2 + b2 cannot be factorised in real numbers, only in complex numbers. The fact that you ask this question indicates that you are nowhere near old enough to be studying complex numbers.
x2 + 1 can't be factored in the real numbers. If complex numbers are acceptable, it can be factored as (x + i)(x - i).