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Two inequalities are equivalent if their solution sets are the same. For example, the inequalities 2x > 6 and 3x > 9 are both equivalent to x > 3.
The answer is like this:equivalent percentage of any no. x out of the number 'n' is:equivalent %=(x/n)*100so,hereequivalent %=(4/6)*100=63.33%
x2 - 5x - 6 = x2 - 6x + x - 6 = x(x - 6) + 1(x - 6) = (x - 6)(x + 1)
x2 - 6x = (x*x - 6*x) = x*(x-6)
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Two inequalities are equivalent if their solution sets are the same. For example, the inequalities 2x > 6 and 3x > 9 are both equivalent to x > 3.
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x>6 or 5<9
The definition of equivalent inequalities: inequalities that have the same set of solutions
x>6 or 5<9
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Just replace the words "is greater than" with the sign ">", and you get the inequality, in this case: x > 6
2x-5<7 2x<12 x<6 -3x+5>11 -3x>6 x<-2
represent x > 6 and x <=18 enter the compound inequality without using and
x = -2t + 2 = -2(t - 1) y = t - 1 So x = -2*y or y = -x/2 Also, t = 0 gives x = 2 and t = 4 gives x = -6 so 0 < t < 4 is equivalent to -6 < x < 2. The answer, therefore is, y = -x/2 for -6 < x < 2 Note: The t-domain is not well defined since the browser does not show any of the inequalities. I have assumed they are all strict inequalities but if they are not, the corresponding inequalities should be used to define the x-domain. However, it is important to remember that the first inequality in t-domain is the second inequality for the x-domain.
Some are, some aren't.
Yes, -6+x is the same as x-6.