Let's do some algebra. Assume that "m" and "n" are any integers. An even number is divisible by 2, so 2m or 2n would be even. An odd number is one that is not divisible by 2, so 2m + 1, or 2n + 1, are odd numbers.
Multiply those two odd numbers together: (2m+1)(2n+1) = 4mn + 2m + 2n + 1. Since the first three parts are even, the added 1 at the end makes the result odd.
The nth odd number is equal to 2n - 1. Therefore, the 200th odd number is equal to (2 x 200) - 1 = 399.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. Odd times even is even.
The sum of any four odd numbers will never be equal to an odd number.
Your question is incomplete. Adding an even number with an odd number will always result in an odd number. Multiplying an even number with an odd number will always result in an even number.
Only integers are even or odd. If a decimal is equal to an integer (for example 24.0 is equal to 24), then it can be even or odd. If a decimal is not equal to an integer (for example, 24.1 is not an integer), then it is neither even nor odd.
All multiples of even numbers will equal an even number.
No. An odd number of negatives in multiplication is negative.
even times even = even odd times odd = odd even times odd = even
Yes. Odd times odd is odd. Odd times even is even. Even times even is even.
An odd number plus an even number will always be an odd number.
How many sections are there and are they equal.
What! Even numbers never equal an odd number. Not ever!
3 odd numbers can't be equal to 50 because: odd number + odd number = even number even number + odd number = odd number thus, adding 3 odd numbers will always give a sum which is an odd number too even number.
An odd number squared would always equal an odd number and an even number squared would always equal an even
Yes, it is.
This is not possible, 27 is an odd number, 4 odd numbers will always equal an even number.
Any such number will be divisible by the even number, and therefore will also be divisible by 2.