Q: Why is 138 divisible by 3?

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Composite since it ends in an even number it will always be divisible by 2

Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.

12345 is divisible by 3 and the answer is 4115

138 = 2 x 3 x 23

2 x 3 x 23 = 138

Related questions

138 is divisible by 6. Any number is divisible by 6 if it is an even number that also is divisible by 3.

Yes. 138 is evenly divisible by three.

It is, but it is NOT evenly divisible.

138 / 9 is equal to 15.33 or 15 with remainder 3.

138 is not divisible by 18.

Yes. The result is 46.

No. 138 is divisible by 2.

No - 138/4 = 34.5

138

No.

I think the question is mistyped, and should be "Is 414 evenly divisible by 3?" i.e. does it divide by 3 without leaving a remainder. The answer is yes. A quick way to tell if a number is divisible by 3 is to add the digits and if the total is divisible by 3, then the number in question is also divisible by 3 4 + 1 + 4 = 9 and 9 is divisible by 3 414 ÷ 3 = 138

Yes. 276 is divisible by these numbers: 1 2 3 4 6 12 23 46 69 92 138 and 276.