No. It is divisible by 5 (it ends in a five) and by 3 (1+2+3+4+5=15 which is divisible by three).
-- It ends in a 5, so 5 is a factor of it. -- The sum of its digits (15) is divisible by 3, so 3 is a factor of it. It probably has tons of other factors, but either of these is enough to prove that it's composite.
12,345 to 3 significant figures is 12,300.
Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.
Well, to find out if any number is divisible by 3, you add up the number's factors. If the number you come up with is divisible by 3, then the entire number is divisible by 3.For example:138= 1+3+8= 1212 is divisible by 3.
It can be divided by 3 as in 12345/3=4115, but not 9 as in 12345/9=1371.6666666666666.
yes 12345 is a prime number
823x15=12345
No. It is divisible by 5 (it ends in a five) and by 3 (1+2+3+4+5=15 which is divisible by three).
All of them.
120
If, when divided by 3, it leaves no remainder. Also, if you add the individual numbers up and that number is divisible by three, the larger one is as well. Example: 12345 adds up to 15. 15 is divisible by three. So is 12345.
12345 × 3 = 37,035
The same as 12345 x 12345 x 12345.The same as 12345 x 12345 x 12345.The same as 12345 x 12345 x 12345.The same as 12345 x 12345 x 12345.
5 ^12
12345 + 12345 = 24690
answer;12345