No. It is divisible by 5 (it ends in a five) and by 3 (1+2+3+4+5=15 which is divisible by three).
-- It ends in a 5, so 5 is a factor of it. -- The sum of its digits (15) is divisible by 3, so 3 is a factor of it. It probably has tons of other factors, but either of these is enough to prove that it's composite.
12,345 to 3 significant figures is 12,300.
To determine if 42 is divisible by 3, you can add up the digits of 42 (4 + 2 = 6) and check if the sum is divisible by 3. Since 6 is divisible by 3, then 42 is also divisible by 3. This is based on the rule that a number is divisible by 3 if the sum of its digits is divisible by 3.
Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.
It can be divided by 3 as in 12345/3=4115, but not 9 as in 12345/9=1371.6666666666666.
yes 12345 is a prime number
823x15=12345
No. It is divisible by 5 (it ends in a five) and by 3 (1+2+3+4+5=15 which is divisible by three).
All of them.
120
If, when divided by 3, it leaves no remainder. Also, if you add the individual numbers up and that number is divisible by three, the larger one is as well. Example: 12345 adds up to 15. 15 is divisible by three. So is 12345.
12345 × 3 = 37,035
The same as 12345 x 12345 x 12345.The same as 12345 x 12345 x 12345.The same as 12345 x 12345 x 12345.The same as 12345 x 12345 x 12345.
5 ^12
12345 + 12345 = 24690
answer;12345