12345 is divisible by 3 and the answer is 4115
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No. It is divisible by 5 (it ends in a five) and by 3 (1+2+3+4+5=15 which is divisible by three).
-- It ends in a 5, so 5 is a factor of it. -- The sum of its digits (15) is divisible by 3, so 3 is a factor of it. It probably has tons of other factors, but either of these is enough to prove that it's composite.
12,345 to 3 significant figures is 12,300.
Suppose x = sqrt(3*a) where a is an integer that is not divisible by 3. then x2 = 3*a which is divisible by 3. but x is not even rational and so is not an integer and is certainly not divisible by 3.
Well, to find out if any number is divisible by 3, you add up the number's factors. If the number you come up with is divisible by 3, then the entire number is divisible by 3.For example:138= 1+3+8= 1212 is divisible by 3.