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8999, 8998, 8997
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∙ 7y ago
Anonymous
Valery
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What are 3 numbers for 9000 as an estimate?
9000 to the nearest thousand, 10000 to the nearest ten thousands and 0 to the nearest million.
What is 3 percent of 9000?
3% of 9000 = 270= 3% * 9000 = 0.03 * 9000 = 270
How can you write 63 as a product of prime numbers?
7*3*3
Write 54 as a product of its prime numbers?
It is: 2*3*3*3 = 54
What is 33 percent and a third of 9000?
33 and 1/3% of 9000 is 3000
What are 3 numbers for 9000 as an estimate?
9000 to the nearest thousand, 10000 to the nearest ten thousands and 0 to the nearest million.
3 numbers whose product is about 9000 estimate?
As a product of its prime factors in exponents: 23*32*53 = 9000
What 3 numbers make the product of 9000?
20.800838230519041145300568243579 * 20.800838230519041145300568243579 * 20.800838230519041145300568243579 = 9000
Write 589043 in eapanded from?
500000+80000+9000+40+3
3 numbers that product is about 9000?
(2) x (3) x (1,500.1) will do it.
How do you write 9000 in scientific notation?
9 x 10^3
What is 3 percent of 9000?
3% of 9000 = 270= 3% * 9000 = 0.03 * 9000 = 270
What numbers between 100 and 9000 are divisible by 3?
There are 2,966 numbers between 100 and 9,000 that are divisible by three.
What are Three numbers whose product is about 9000 using multiplication?
3 x 3 x 1000
What are all 4 digit numbers that are formed from 0 1 2 3 4 5 6 7 8 9 all 9000 of them?
We have better things to do with our time. You know how to write the numbers between 1000 and 9999.
What are 3 numbers whose product is 9000?
9000x1 1x9000 900x1
3 numbers whose product is about 9000?
Prime factorisation of 9000 = 2*2*2*3*3*5*5*5 Well 9000 can be expressed as the product of (2*2*2)*(3*3)*(5*5*5) or 8*9*125 So, 9000 can be expressed as the product of 8,9 and 125. It can be expressed as 2*(2*2*5*5)*(3*3*5) i.e. 9000 = 2*100*45 By using the method of Prime factorisation, we can find many cases in which product of 3 numbers is 9000. We can also express it as 900*(1/10)*100, which cannot be done using P.F. of 9000. We can find a large number of cases in which product of three numbers is 9000. We can find numbers by this method: Assume any three variables and put their product equal to 9000 i.e. x*y*z = 9000 where x,y and z are real numbers. Put any value of x, say 34 and any value of y, say 23, then on putting the values we can find the value of z i.e. 34*23*z = 9000 782*z = 9000 z = 11.5089 So, this method works better than Prime Factorisation.
