(2) x (3) x (1,500.1) will do it.
20.800838230519041145300568243579 * 20.800838230519041145300568243579 * 20.800838230519041145300568243579 = 9000
As a product of its prime factors in exponents: 23*32*53 = 9000
3 x 3 x 1000
The number 9000 can be expressed as the product of its prime factors, which are 2^3 * 3^2 * 5^3. In terms of mathematical operations, 9000 can be reached by multiplying 9 by 1000, or by adding 8000 and 1000. Additionally, 9000 can be represented as the sum of consecutive numbers, such as 4499 + 4501.
The answer is 400 because when you take three numbers whose product is 9000, one of the possible sets is 10, 30, and 30. When you multiply these three numbers (10 × 30 × 30), the product equals 9000. If you are looking for a specific scenario where the result is 400, you may be referring to a different interpretation or context of the problem. Could you please clarify the conditions or constraints of the question?
20.800838230519041145300568243579 * 20.800838230519041145300568243579 * 20.800838230519041145300568243579 = 9000
As a product of its prime factors in exponents: 23*32*53 = 9000
9000x1 1x9000 900x1
3 x 3 x 1000
Prime factorisation of 9000 = 2*2*2*3*3*5*5*5 Well 9000 can be expressed as the product of (2*2*2)*(3*3)*(5*5*5) or 8*9*125 So, 9000 can be expressed as the product of 8,9 and 125. It can be expressed as 2*(2*2*5*5)*(3*3*5) i.e. 9000 = 2*100*45 By using the method of Prime factorisation, we can find many cases in which product of 3 numbers is 9000. We can also express it as 900*(1/10)*100, which cannot be done using P.F. of 9000. We can find a large number of cases in which product of three numbers is 9000. We can find numbers by this method: Assume any three variables and put their product equal to 9000 i.e. x*y*z = 9000 where x,y and z are real numbers. Put any value of x, say 34 and any value of y, say 23, then on putting the values we can find the value of z i.e. 34*23*z = 9000 782*z = 9000 z = 11.5089 So, this method works better than Prime Factorisation.
The number 9000 can be expressed as the product of its prime factors, which are 2^3 * 3^2 * 5^3. In terms of mathematical operations, 9000 can be reached by multiplying 9 by 1000, or by adding 8000 and 1000. Additionally, 9000 can be represented as the sum of consecutive numbers, such as 4499 + 4501.
300 x 300
The product is: 81,000,000
They are 1,2, and 4,500
9000 to the nearest thousand, 10000 to the nearest ten thousands and 0 to the nearest million.
9000 = 9000. No other number equals 9000.
7*9000 = 63000