As a product of its prime factors in exponents: 23*32*53 = 9000
(2) x (3) x (1,500.1) will do it.
3 x 3 x 1000
The number 9000 can be expressed as the product of its prime factors, which are 2^3 * 3^2 * 5^3. In terms of mathematical operations, 9000 can be reached by multiplying 9 by 1000, or by adding 8000 and 1000. Additionally, 9000 can be represented as the sum of consecutive numbers, such as 4499 + 4501.
The product of 5 x 6 x 7 is 210.
As a product of its prime factors in exponents: 23*32*53 = 9000
(2) x (3) x (1,500.1) will do it.
9000x1 1x9000 900x1
3 x 3 x 1000
Prime factorisation of 9000 = 2*2*2*3*3*5*5*5 Well 9000 can be expressed as the product of (2*2*2)*(3*3)*(5*5*5) or 8*9*125 So, 9000 can be expressed as the product of 8,9 and 125. It can be expressed as 2*(2*2*5*5)*(3*3*5) i.e. 9000 = 2*100*45 By using the method of Prime factorisation, we can find many cases in which product of 3 numbers is 9000. We can also express it as 900*(1/10)*100, which cannot be done using P.F. of 9000. We can find a large number of cases in which product of three numbers is 9000. We can find numbers by this method: Assume any three variables and put their product equal to 9000 i.e. x*y*z = 9000 where x,y and z are real numbers. Put any value of x, say 34 and any value of y, say 23, then on putting the values we can find the value of z i.e. 34*23*z = 9000 782*z = 9000 z = 11.5089 So, this method works better than Prime Factorisation.
The number 9000 can be expressed as the product of its prime factors, which are 2^3 * 3^2 * 5^3. In terms of mathematical operations, 9000 can be reached by multiplying 9 by 1000, or by adding 8000 and 1000. Additionally, 9000 can be represented as the sum of consecutive numbers, such as 4499 + 4501.
9000 to the nearest thousand, 10000 to the nearest ten thousands and 0 to the nearest million.
The product of 5 x 6 x 7 is 210.
There are many possible answers to this question ... for example, 9000, 2000, and 111. Can you be more specific?
As a product of its prime factors: 3*3*3*11 = 297
There is no set of 3 consecutive odd numbers whose product is 6,873. However, there is a set of 3 consecutive odd numbers whose sum is 6,873: 2289, 2291, and 2293.
The prime numbers 2 and 3 have 6 as their product when multiplied.