Subtract first from second gives -4x = 16 so x = -4 and y = -7
If: 5x+2y = 9 Then: y = -2.5x+4.5 in slope intercept form
There are 2 unknowns
A straight line through the points (0, 1) and (-0.4, 0).
5x - 3y -7x + 2y +3x = (5-7+3)x + (-3+2)y = x - y
First get y in terms of x: 5x-2y=-12 ----- -2y=-12-5x ------ y=6+(5/2)x Sub into other equation: 2x+3y=-1 ---- 2x+3(6+(5/2)x)=-1 Solving for x gets: x= -2 Sub into other equation: 5x-2y= -12 --- 5(-2)-2y= -12 --- y=1 So x= -2, and y= 1
(-4, -1)
(3, 2)
Multiply the bottom equation by -1
If: 3x+2y = 5x+2y = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtract the 1st equation from the 2nd equation: 2x = 0 or x = o By substitution: x = 0 and y = 3.5
10x + 2y + 8z - 5x + 4z - 4y = 10x - 5x + 2y - 4y + 8z + 4z = (10 - 5)x + (2 - 4)y + (8 + 4)z = 5x - 2y + 12z
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
x = 3 and y = 2
(1, 0)
If: 3x+2y = 5x+2y = 7 which is the same as 7 = 7 = 7 Then: 3x+2y = 7 and 5x+2y = 7 Subtracting equations: x = 0 Therefore by substitution: x = 0 and y = 3.5
If: 5x+2y = 9 Then: y = -2.5x+4.5 in slope intercept form
Both of them are equations!The solution is (x, y) = (2, 1).
5x-2y+3z-2x-y-4z=3x-3y-z