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6x-3y=30 4x=2-y There are many ways to find the values of x and y. elimination substitution matrices on and on... Here's one. Set them both equal to y y=2x-10 y=2-4x So the right sides are both equal to y, therefore, they are equal to each other. 2x-10 = 2-4x 6x=12 x=2 plug 2 in for x on one of the equations y=2-4x y=2-4(2) y=-6
4x+6x=30 is the same as: 10x=30 so we divide by 10 and get: x=3 (I do not see how this relates to calculus, but O.K.)
6x-3y
4x + 6 = 6x - 12-4x -4x6 = 2x - 12+12 +1218 = 2xx=9
2x -3 - 6x = 0 -3 = 6x - 2x -3 = 4x x = -3/4
-4
6x + 3y + 6y - 2x = (6x - 2x) + (3y + 6y) = 4x + 9y
4x-2y
2x + 3y + 4x + 9y = 2x + 4x + 3y + 9y = 6x + 12y which can be simplified to 6(x + 2y)
6x plus 3y minus 2x plus 5y equals 4x plus 8y.
6x - 3y = 304x = 2 - y4x = 2 - yy = 2 - 4x (substitute 2 - 4x for y into the first equation)6x - 3y = 306x - 3(2 - 4x) = 306x - 6 + 12x = 3018x = 36x = 2y = 2 - 4x (substitute 2 for x)y = 2 - 4(2) = 2 - 8 = -6So the solution is x = 2, and y = -6.x + y = 2 + -6 = -4Thus, it is true that x + y = -4.
6x-3y=30 4x=2-y There are many ways to find the values of x and y. elimination substitution matrices on and on... Here's one. Set them both equal to y y=2x-10 y=2-4x So the right sides are both equal to y, therefore, they are equal to each other. 2x-10 = 2-4x 6x=12 x=2 plug 2 in for x on one of the equations y=2-4x y=2-4(2) y=-6
It is the same as: 6x+4y
6x-3y=30 and 4x=2-y then find x+y.6x-3y = 304x = 2-yx=5+y/2 from first equation, now sub into second20+2y =2-ygiving y = -6sub y=-6 into first equation6x+18 = 30giving x= 2x= 2, y=-6
6x - 4y
6x plus 4y
2x + 6 - 6x = 30= 6 - 4x = 30= -4x = 24= 4x = -24= x = -6