3x+5y=48 5y=48-3x-3x+5y=12 -3x+(48-3x)=12-6x=-36x=65y=48-3(6)5y=30y=6(6,6)
Because of the limitations of the question software, it was not possible to determine what the original equation was supposed to be, so we assumed it is 3x + 5y = 7. It could have just as easily been 3x - 5y = 7, or even 3x/5y = 7.So, let's solve them all for x.3x + 5y = 73x = 7 - 5yx = (7 - 5y)/3How about 3x - 5y = 7?3x - 5y = 73x = 7 + 5yx = (7 + 5y)/3And 3x/5y = 7?3x/5y = 73x = 35yx = 35y/3 Solving for y The above equations wrote the equation so that x is a function of y, not the other way around. Here's how to rewrite the equation so that y is a function of x: 3x + 5y = 7 5y = -3x + 7 y = (-3x + 7)/5
9x + 8y = (9 x 6) + (8 x 3) = 54 + 24 = 78
If x equals 10 and y equals 10, then 9x plus 8y equals 170.
Multiply the first equation by 3 to give 9x + 15y = 21
3x - 8y + 2x - 5 - 5y = 5x -13y - 5
Well, the way you wrote it, you would have:(4x - 5y - 3) x 3x + 5ywhich would give12x^2 - 15xy - 9x + 5yBut, if you meant the quantity (3x + 5y), then you would have:(4x - 5y - 3) x (3x + 5y)which would give12x^2 - 15xy - 9x + 20xy - 25y^2 - 15yand combining terms12x^2 - 25y^2 + 5xy - 9x - 15y
If you mean: -8y-(x-4x)+3y then it is 3x-5y simplified
8y-3x
x+8y=28 -3x+5y=3
(2, 3)
If you mean (9x-8y)(9x+8y) then it is 81x^2 minus 64y^2
A: 11x = 5y + 80 B: 9x - 15y = 120 A: 11x - 5y = 80 B: 9x - 15y = 120 A: 11x - 5y = 80 B: 3x - 5y = 40 A - B: 8x = 40 x = 5 Now we can plug that value of x into one of the original equations to solve for y: 11(5) - 5y = 80 55 - 5y = 80 -5y = 25 y = -5
7 + 8y - 3y + 2 =7 + 2 + 8y - 3y = 9 + 8y - 3y = 9 + 5y
The standard form is 3x - 8y - 4 = 0
9x plus 8y
3x. 15x - 9x = 6x 9x - 6x = 3x 6x - 3x = 3x 3x - 3x = 0