0
2x^3-3x^2-11x+7x+32x^2-9x+16 R -41x+3 l 2x^3-3x^2-11x+7-(2x^3+6x^2)-9x^2-11x+7-(-9x^2-27x)16x+7-(16x+48)-412x^2-9x+16-[41/(x+3)]
It is f(x) = 7/x.
use the tens place to multiply by 2, then use the number to subtract the ones place.The answer can be divided by 7, if not it will be 0.use 490 as an example.9x2=18.18-4=14.14 divided by 7 is 2. so 49 can be divide by 7
Dividend: 4x^4 -x^2 +17x^2 +11x +4 Divisor: 4x +3 Quotient: x^3 -x^2 +5x -1 Remainder: 7
2.3333
0.4286
6 divided by 7 times 3 divided by 5 = 0.51428571428
3/7 x 7/8 = 21/56 or 3/8
3
0.1111
3 divided by 7 is:3/7 = 0.428571428 calculating to 9 decimal places.
7 divided by 13 times 2 divided by 3 is 14/39
3 and 6/7 divided by 1 and 2/7 = 3
3/7
It is: 11 divided by 3/7 = 77/3 or 25 and 2/3
3/7 divided by 9