y=f(x)= x(2x+y)=7 f(x)=2x^2 +xy -7 = 0 y=2x^2 +xy -7 y-xy -7 + 2x^2 = 0 y(1-x)=2x^2-7 y=(2x^2-7) / (1-x) Excuse the working. Y equals 2 X squared minus 7 all divided by 1-X
d/dx [f(x) + g(x)] = d/dx [f(x)] + d/dx [g(x)] or f'(x) + g'(x) when x = 3, d/dx [f(x) + g(x)] = f'(3) + g'(3) = 1.1 + 7 = 8.1 d/dx [f(x)*g(x)] = f(x)*d/dx[g(x)] + d/dx[f(x)]*g(x) when x = 3, d/dx [f(x)*g(x)] = f(3)*g'(3) + f'(3)*g(3) = 5*7 + 1.1*(-4) = 35 - 4.4 = 31.1
f(x)=x+1 g(f(x))=x f(x)-1=x g(x)=x-1
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)
Yes
What divided by 7 equals 8? In other words, you have an unknown number (X), and then if you divide that X by 7 you get 8. Then what is that X? The equation to calculate what divided by 7 equals 8 is as follows: X/7 = 8 Where X is the answer. When we solve the equation by multiplying each side by 7, you get get: X = 56 Therefore, the answer to what divided by 7 equals 8 is 56.
A lot of answers... for example, 49 divided 7 equals 7.
f(x) = 2x + 8 f(x) = -7 → 2x + 8 = -7 → 2x = -15 → x = -7½ = -7.5
Let, f (x) = - 5x - 9 Therefore, f(x) + 7 = - 5x - 9 + 7 f(x) + 7 = - 5x - 2
x/7 = 14 x = 98
F(a)
x=x-1/x
x/7 = 40 Therefore, x = 7 x 40 x = 280
f(x)=5x, g(x)=3x-7 gf(x)= = g(f(x)) = g(5x) = 3*(5x) - 7 = 15x-7 So gf(4) = 15*4-7=53
22
x = 47/42
(x-7)/12 = x/15 x-7 = 0.8x 0.8x-x = -7 -0.2x = -7 x = 7/0.2 >x = 35<