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Let the length of the square be x and the height of the box be h. The volume of the box is the x2h=2ft2 The surface area (remember the top is open) is x2+4xh Using the first equation, make h the subject of the formula. h=2/(x2) and substitute this into the surface area formula. We then have SA=x2+8/x We have a minimum materials used when the derivative of this equation is equal to 0 SA'(derivative)=2x-8/(x2)=0 2x=8/(x2) 2x3=8 x3=4 x=1.59 ft h=2/x2=0.79 So the dimensions are 1.59 x 1.59 x 0.79 (2 dec pl.)

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Q: A box is to have a square base an open top and volume of 2ft Find the dimensions of the box to the nearest inch that uses the least amount of material?
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