In standard form, -6 + y = 2x is 2x - y + 6 = 0
2y - 4x = 12 is 4x - 2y + 12 = 0
Each coefficient of the second is twice the corresponding coefficient of the first. So the equations are the same (and therefore dependent).
In standard form, -6 + y = 2x is 2x - y + 6 = 0
2y - 4x = 12 is 4x - 2y + 12 = 0
Each coefficient of the second is twice the corresponding coefficient of the first. So the equations are the same (and therefore dependent).
In standard form, -6 + y = 2x is 2x - y + 6 = 0
2y - 4x = 12 is 4x - 2y + 12 = 0
Each coefficient of the second is twice the corresponding coefficient of the first. So the equations are the same (and therefore dependent).
In standard form, -6 + y = 2x is 2x - y + 6 = 0
2y - 4x = 12 is 4x - 2y + 12 = 0
Each coefficient of the second is twice the corresponding coefficient of the first. So the equations are the same (and therefore dependent).
In standard form, -6 + y = 2x is 2x - y + 6 = 0
2y - 4x = 12 is 4x - 2y + 12 = 0
Each coefficient of the second is twice the corresponding coefficient of the first. So the equations are the same (and therefore dependent).
A graph that has 1 parabolla that has a minimum and 1 positive line.
Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12
To solve for two unknown variables (x and y) you require two independent equations,
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
why will the equations x+14=37 and x-14=37 have different solutions for x
When (the graph of the equations) the two lines intersect. The equations will tell you what the slopes of the lines are, just look at them. If they are different, then the equations have a unique solution..
Inconsistent linear equations in two variables.
The two equations represent the same straight line.
Simultaneous equations.
1
When x = -2 then y = 4 which is the common point of intersection of the two equations.
It's an inconsistent pair of equations, for which there is no solution.
The lines are parallel.
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
1st equation: x-y-z = 0 2nd equation: 2x-y+2z = 1 3rd equation: x-y+z = -2 They appear to be simultaneous equations dependent on each other for the solutions which are: x = 4, y = 5 and z = -1
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. However, it appears as if the two equations are essentially the same and therefore there are infinitely many solutions.
No.