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Q: Can definite integral be negative
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How do you integrate periodic functions?

Same as any other function - but in the case of a definite integral, you can take advantage of the periodicity. For example, assuming that a certain function has a period of pi, and the value of the definite integral from zero to pi is 2, then the integral from zero to 2 x pi is 4.


How is definite integral connected to area under the curve?

If the values of the function are all positive, then the integral IS the area under the curve.


What is the relation between definite integrals and areas?

Consider the integral of sin x over the interval from 0 to 2pi. In this interval the value of sin x rises from 0 to 1 then falls through 0 to -1 and then rises again to 0. In other words the part of the sin x function between 0 and pi is 'above' the axis and the part between pi and 2pi is 'below' the axis. The value of this integral is zero because although the areas enclosed by the parts of the function between 0 and pi and pi and 2pi are the same the integral of the latter part is negative. The point I am trying to make is that a definite integral gives the area between a function and the horizontal axis but areas below the axis are negative. The integral of sin x over the interval from 0 to pi is 2. The integral of six x over the interval from pi to 2pi is -2.


What is the relationship of integral and differential calculus?

We say function F is an anti derivative, or indefinite integral of f if F' = f. Also, if f has an anti-derivative and is integrable on interval [a, b], then the definite integral of f from a to b is equal to F(b) - F(a) Thirdly, Let F(x) be the definite integral of integrable function f from a to x for all x in [a, b] of f, then F is an anti-derivative of f on [a,b] The definition of indefinite integral as anti-derivative, and the relation of definite integral with anti-derivative, we can conclude that integration and differentiation can be considered as two opposite operations.


What is the fundamental theorem of calculus?

If df(x)/dx = g(x), then integral [from a to b] g(x) dx = f(b)-f(a). In plain English: the definite integral can be calculated by finding the antiderivative, evaluating it at the endpoints, and subtracting.

Related questions

How do you convert a percentage into a fraction?

Divide by the sum of the primitive function of the percentage, accounting for a negative definite integral.


Application of definite Integral in the real life?

Application of definitApplication of definite Integral in the real life


How do you explain negative integral?

The definite integral of a function: y = f(x) from x = a to x = b is equal to the area between the function curve and the 'x' axis from x = a to 'x' = b.


What is the indefinite integral?

An indefinite integral is a version of an integral that, unlike a definite integral, returns an expression instead of a number. The general form of a definite integral is: ∫ba f(x) dx. The general form of an indefinite integral is: ∫ f(x) dx. An example of a definite integral is: ∫20 x2 dx. An example of an indefinite integral is: ∫ x2 dx In the definite case, the answer is 23/3 - 03/3 = 8/3. In the indefinite case, the answer is x3/3 + C, where C is an arbitrary constant.


Geometrically the definite integral gives the area under the curve of the integrand Explain the corresponding interpretation for a line integral?

gemetrically the definite integral gives the area under the curve of the integrand. explain the corresponding interpretation for a line integral.


What is the definite integral of 1 divided by x squared?

For it to be a definite integral, you would need to specify a range. We can however give you the indefinite integral. The easiest way to do this is to think of it not as a fraction, but as a negative exponent: 1/x2 = x-2 It then becomes quite easy to integrate, as we can say in general: ∫(axn) dx = ax(n + 1) / (n + 1) + C In this case then, we have: ∫(x-2) dx = -x-1 + C, or -1/x + C


How do you integrate periodic functions?

Same as any other function - but in the case of a definite integral, you can take advantage of the periodicity. For example, assuming that a certain function has a period of pi, and the value of the definite integral from zero to pi is 2, then the integral from zero to 2 x pi is 4.


Application of definite Integral in the real life Give some?

What are the Applications of definite integrals in the real life?


How is definite integral connected to area under the curve?

If the values of the function are all positive, then the integral IS the area under the curve.


What is the part of speech for integrate?

"integral" is primarily an adjective, but in calculus it is usually a noun, as in "the definite integral of a function."


What is the difference between definite integral and line integral?

Both kinds of integrals are essentially calculations of areas under curves. In a definite integral the surface whose area is to be calculated is planar. In a line integral the surface whose area to be calculated might occupy two or more dimensions. You might be interested in the animated diagrams in the wikipedia article for the line integral.


What is trapizoidal rule?

It is a way to approximate a definite integral using trapezoids.