36
x-14 = 20 x = 20+14 x = 34
The inequality sign is neglected due to the omitted punctuation for the question. Assume x + 8 ≤ 14. Then, subtract both sides to get: x ≤ 6. If x + 8 < 14, then x < 6. If x + 8 > 14, then x > 6. If x + 8 ≥ 14, then x ≥ 6.
-24
6
27 x 14 = 378
1 row of 14 dots
-41 Let X= required number: X + 14 = -27 X= -27 - 14 X= -41
x+y=27 x=14 27-14=y y=13
Let the first number be x and the second number is 27 − x. [As the sum of both the numbers is 27] Therefore, their product = x (27 − x) It is given that the product of these numbers is 182. x (27 – x) = 182 x2 + 27x - 182 = 0 Changing the signs on both sides we get,x2 - 27x + 182 = 0 Factorizing we get , 13 and 14 are the numbers whose sum is 27 and product is 182 x2 – 13x – 14x + 182 = 0 = x(x – 13) – 14 (x – 13)= 0 = (x – 13) (x – 14) = 0 Either x – 13 = 0 or x − 14 = 0 i.e., x = 13 or x = 14 If first number = 13, then Other number = 27 − 13 = 14 If first number = 14, then Other number = 27 − 14 = 13 Therefore, the numbers are 13 and 14.
3 with 14 remaining95 - 14 = 81 = 27 x 3
14 x 60 = 840 867 - 840 = 27 Answer: 14 hours 27 minutes
14 x 27/144 = 2.625 (two and five eighths) sqft.
Option 1) Use a temporary variable: int x = array[i]; array[i] = array[i+1]; array[i+1] = x; Option 2) Use bit operators: array[i] ^= array[i+1] ^= array[i];
27 x 1 = 27 27 x 2 = 54 27 x 3 = 81 27 x 4 = 108 27 x 5 = 135 27 x 6 = 162 27 x 7 = 189 27 x 8 = 216 27 x 9 = 243 27 x 10 = 270 27 x 11 = 297 27 x 12 = 324 27 x 13 = 351 27 x 14 = 378 27 x 15 = 405 27 x 16 = 432 27 x 17 = 459 27 x 18 = 486 27 x 19 = 513 27 x 20 = 540 27 x 21 = 567 27 x 22 = 594 27 x 23 = 621 27 x 24 = 648 27 x 25 = 675 27 x 26 = 702 27 x 27 = 729 27 x 28 = 756 27 x 29 = 783 27 x 30 = 810 ...
2 x 7 = 14
x+y=40 + x-y=14 2x =54 x=27 y=13