so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1
7x + 8 = 10x - 2 ∴ 3x = 10 ∴ x = 10/3
3x2 - 19x - 14 = 0 3x2 - 21x + 2x - 14 = 0 3x(x - 7) + 2(x - 7) = 0 (x - 7)(3x + 2) = 0 x - 7 = 0 or 3x + 2 = 0 x = 7 or x = -2/3
y - 8 = x^2 + 12x + 36 y - 8 = (x + 6)^2 y = (x + 6)^2 + 8 or f(x) = (x + 6)^2 + 8 So -h = 6 so that h = -6, and k = 8
(x + 2)(x - 4)
14
(-8) x (-7) - 14 = 42
x=14
x=1
14
x = 34 {add 14 to both sides: x - 14 + 14 = 20 + 14 = 34}
X + y = 8 x - y = 6 add equations to eliminate y 2x = 14 x = 7 substitute 7 + y = 8 y = 1
If X - 8 = -1 then X = -1 +8 Therefore X = 7
14
x - 7 = 8 x = 7 + 8 x = 15
x = -2/3,7/6
8 x 14