Derivative of 1/x 1/x = x-1 Take the derivative (-1)x(-1-1) = -x-2 = 1/x2
The derivative of sec(x) is sec(x) tan(x).
∫ 4/x dx= 4 ∫ 1/x dx= 4ln(x) + CThis is true for three reasons:the derivative of the term ln(x) is equal to 1/x4 is a constant factor of the term, and can be moved out of the integralC is an unknown constant, because we're looking at an indefinite integralYou can confirm this by taking the derivative of 4ln(x), which gives you 4/x, the original term.
The derivative is 1/(1 + cosx)
The derivative of sin(x) is cos(x).
4/x can be written as 4x-1 (the power of negative 1 means it is the denominator of the fraction) 4*-1 = -4 Therefore, the derivative is -4x-2
Derivative of 1/x 1/x = x-1 Take the derivative (-1)x(-1-1) = -x-2 = 1/x2
2 x 2 = 4. 4 is a constant. The derivative of a constant is always 0. Therefore, The derivative of 2 x 2 is zero.
(4lnx)' =4*1/x=4/x
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The derivative of x^n is nx^(n-1) any n. The derivative of x^4 is 4x^3.
-4/x2
Find the derivative of Y and then divide that by the derivative of A
find anti derivative of f(x) 5x^4/3 + 8x^5/4
It is -1 over x-squared.
(-2 x2)' = -4 x
X^4 ? 4x^3