If it's tan(x3), the the thingy is 3x2/(cos2(x3)) i think Else, if it's tan(3x), then it's 3/(cos2x) If you need more help with this, search "chain rule" and "derivative" on wikipedia.
Let y = x3 - 8, then y' = 3x2 + 0 = 3x2.
-4 / x3
x*x1/2= x3/2 Derivative = 3/2 * x1/2
Regardless of what 'x' is, (x)0 = 1 . tan(1 radian) = 1.55741 (rounded) tan(1 degree) = 0.01745 (rounded) We can't remember the derivative of the tangent right now, but it doesn't matter. This particular tangent is a constant, so its derivative is zero.
If it's tan(x3), the the thingy is 3x2/(cos2(x3)) i think Else, if it's tan(3x), then it's 3/(cos2x) If you need more help with this, search "chain rule" and "derivative" on wikipedia.
the derivative of 3x is 3 the derivative of x cubed is 3 times x squared
-12sin(x3)x2
(x3)'=3x2(x3)''=(3x2)'=6x
The derivative of tan(x) is sec2(x).(Which is the same as 1/cos2(x).
Let y = x3 - 8, then y' = 3x2 + 0 = 3x2.
-4 / x3
It is -2*(3x2 - 7)*(x3 - 7x)-3
0.3333
The derivative of sec(x) is sec(x) tan(x).
x*x1/2= x3/2 Derivative = 3/2 * x1/2
d/dx(x4/4) = x3