Well, let's take a moment to look at this equation. If we substitute x = 0 and y = -5 into the equation y - 6x - 5, we get -5 - 6(0) - 5. Simplifying this, we get -5 - 0 - 5, which equals -10. So, unfortunately, (0, -5) does not make the equation true. But don't worry, mistakes are just happy little accidents that help us learn and grow.
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x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
x2 + 6x = 16x2 + 6x - 16 = 0(x + 8)(x - 2) = 0x + 8 = 0 or x - 2 = 0x = -8 or x = 2Since it is given that x > 0, then x = -8 is not a solution of the equation. Thus, the only solution is x = 2.
Once you find the y-intercept(s) you'll be steps away from finding the x-intercept(s). The original equation is 6x - 3y = 18.Step 1 is to solve for y by isolating y on one side of the equation.6x - 3y = 18-3y = 18 - 6x-3y = -6x + 18The reason I reorganized the terms, is so that the equation is in the Slope-Intercept form.y = (-6x/-3) + (18/-3)y = 2x + (-6)y = 2x - 6This equation is in the Slope-Intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. So the y-intercept is -6. Now onto the x-intercept. To get x-intercept(s), keep the equation in the Slope-Intercept form and set y equal to zero.y = 2x - 60 = 2x - 60 + 6 = 2x6 = 2x6/2 = x3 = xSo the x-intercept is 3. Now what does these two intercepts tell you? On a graph with a y- and x-axis, when x = 0 then y = -6, which means one of the points on your line is at (0 , -6). The same thing is true for the x-intercept. When y = 0 then x = 3, and that is where your second point is, at (3 , 0). Connect those two points and you'll have your line.
2x -3 - 6x = 0 -3 = 6x - 2x -3 = 4x x = -3/4