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Well, let's take a moment to look at this equation. If we substitute x = 0 and y = -5 into the equation y - 6x - 5, we get -5 - 6(0) - 5. Simplifying this, we get -5 - 0 - 5, which equals -10. So, unfortunately, (0, -5) does not make the equation true. But don't worry, mistakes are just happy little accidents that help us learn and grow.
Is (7, 3) a solution to the equation y = 3x?
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What are the solutions for the quadratic equation x2 plus 6x equals 16?
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
What is 2x3 plus 11x equals 6x?
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
If x is a positive integer solve x2 plus 6x equals 16?
x2 + 6x = 16x2 + 6x - 16 = 0(x + 8)(x - 2) = 0x + 8 = 0 or x - 2 = 0x = -8 or x = 2Since it is given that x > 0, then x = -8 is not a solution of the equation. Thus, the only solution is x = 2.
What are the x- and y-intercepts of the linear function 6x - 3y equals 18?
Once you find the y-intercept(s) you'll be steps away from finding the x-intercept(s). The original equation is 6x - 3y = 18.Step 1 is to solve for y by isolating y on one side of the equation.6x - 3y = 18-3y = 18 - 6x-3y = -6x + 18The reason I reorganized the terms, is so that the equation is in the Slope-Intercept form.y = (-6x/-3) + (18/-3)y = 2x + (-6)y = 2x - 6This equation is in the Slope-Intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. So the y-intercept is -6. Now onto the x-intercept. To get x-intercept(s), keep the equation in the Slope-Intercept form and set y equal to zero.y = 2x - 60 = 2x - 60 + 6 = 2x6 = 2x6/2 = x3 = xSo the x-intercept is 3. Now what does these two intercepts tell you? On a graph with a y- and x-axis, when x = 0 then y = -6, which means one of the points on your line is at (0 , -6). The same thing is true for the x-intercept. When y = 0 then x = 3, and that is where your second point is, at (3 , 0). Connect those two points and you'll have your line.
How do you work out 2x - 3 - 6x?
2x -3 - 6x = 0 -3 = 6x - 2x -3 = 4x x = -3/4
What is the answer to this equation 3x2 plus 6x plus 24 equals 0?
From what i understand the equation is like this; (3 * 2 ) + 6x + 24 = 0 6 + 6x +24 = 0 6x = - 24 - 6 6x = - 30 x = - 5
Which equation is equivalent to -6x-6?
0
How do you make a flowchart with a equation?
Lets say that your equation is 2(3x + 1) To make a flow chart you need to make circles ( depending on how long the equation is) and arrows ex. 0->0->0-> etc. first on the first circle put the number 2. then on the arrow the number and the operation need to ex. multiply by 2 ( in this case x 3 times multiply) then on the next circle you should have 6x ( 2 multiplied by 3x=6x). Then do the remaining ( add 1 for this equation) 6x+1= 6x=1 so this is how you simplify the equation from 2(3x + 1)+ 6x+1
What is the answer to the equation X plus 3 times X plus 3 equals 36?
The 'answer' is the number that 'x' must be in order to make the equation true.(x + 3) (x + 3) = 36Expand the left side:x2 + 6x + 9 = 36Subtract 36 from each side:x2 + 6x - 27 = 0Factor the left side:(x + 9) (x - 3) = 0This equation is true if either factor = 0:x + 9 = 0 ===> x = -9x - 3 = 0 ===> x = 3Both values for 'x' are "answers" to the original equation.
How do you know if a solution is always true or sometimes true?
We call a solution any value of the variable which satisfies the given equation. If the number of values you get (which always satisfy the equation) is a finite number, then the equation is sometimes true (meaning it is true only for those values you got). ex. x + 3 = 5 is true only when x is 2. x2 - 5 = 4 is true only when x is -3 or 3. √x = 7 is true only when x is 49. (check:) 2(3x - 1) = 6x - 2 is always true, meaning for any value that x can take on, both sides becomes equal when x is replaced by it. 2(3x - 1) = 6x - 26x - 2 = 6x - 2 (both sides seems to be equal) , or subtract 6x and add 2 to both sides 0 = 0 a true statement. Since 0 = 0 is an equivalent statement to the original equation and it is a true one, then the original equation must be also a true statement. Thus, there are infinitely many solutions for the given equation. Therefore, the given equation is always true. Sometimes, before you start to solve an equation, you need to exclude some value(s) for the variable of being a solution, because they can make the equation undefined. For example, if the variable happens to be in the denominator, you have to exclude all the values of the variable that make the denominator equal to zero.
Solve the equation 6x plus 5?
6x + 5 = 0 (I'm assuming) 6x = -5x = -5/6
What are the solutions to this equation 9x2 plus 6x-7 equals 0?
9x2+6x-7 = 0 Using the quadratic equation formula:- x = 0.6094757082 or x = -1.276142375
What are the solutions for the quadratic equation x2 plus 6x equals 16?
x2 + 6x = 16=> x2 + 6x - 16 = 0=> x2 + 8x -2x - 16 = 0=> (x+8)(x-2) = 0=> x = -8 or x = 2So, the solutions of the quadratic equation x2 + 6x = 16 are -8 and 2.
4x plus 6 equals 6x-12?
Given, that 4x + 6 = 6x - 12; then, (6x - 12) - (4x + 6) = 0, 2x - 18 = 0, and 2x = 18. Thus, x = 9. Checking, we substitute 9 for x in the equation: 4(9) + 6= 6(9) - 12; whence, 36 + 6 = 54 - 12, and 42 = 42, which is patently true. What this means is that the original equation is true exactly when x = 9; otherwise, it is false. We call 'x = 9' the solution to the given equation.
What is radical sign 6x plus 1 equals x-1?
sqrt(6x + 1) = (x - 1)Square each side of the equation:6x + 1 = (x - 1)26x + 1 = x2 - 2x + 1Subtract 6x from each side:1 = x2 - 8x + 1Subtract 1 from each side:x2 - 8x = 0Factor the left side:x (x - 8) = 0This equation is true if [ x = 0 ] and also if [ x = 8 ]. We'll have to checkboth of them and see if they solve the original equation.Check (x = 0) :sqrt(6x + 1) = sqrt(1) = +1 or -1(x - 1) = (0 - 1) = -1 yay!Check (x = 8) :sqrt(6x + 1) = sqrt(48 + 1) = sqrt(49) = +7 or -7(x - 1) = (8 - 1) = 7 yay!Both (x = 0) and (x = 8) make the original equation a true statement,so those are your solutions.
Six x squared plus twenty one x - forty five?
Assume the question refers to solving the quadratic equation 6x2 +21x - 45 = 0, then :-This equation can be factored 6x2 + 21x - 45 = (6x - 9)(x + 5) = 0This holds true when either 6x - 9 or x + 5 = 0When 6x - 9 = 0 then x = 9/6 = 1.5 : When x + 5 = 0 then x = -5
What is the y intercept for this equation 6x - y equals 9?
-3
