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What is the integral of arcsinxdx?
The integral of arcsin(x) dx is x arcsin(x) + (1-x2)1/2 + C.
How do you solve tan x is equal to 3.0?
You can use the arctangent or the reverse tangent to solve for x, which is denoted by arctan or tan^-1. If tan [x] = 3, then arctan [3] = x. This applies to all trigonometric functions (ex. if sin [x] = 94, then arcsin [94] = x. Punch that into your calculator and the answer will be: arctan [3.0] = 71.565 (degrees) arctan [3.0] = 1.249 (radians)
0 pi is not a point on the graph of which inverse function?
Arcsin
Why inverse sine function also known as arc sine?
Yes, it is called arcsin.
What is the inverse sine of 0.75?
arcsin(.75)≈0.848062079
How do you solve sin parenthesis arcsin parenthesis 2 over 3 closed parenthesis and another closed parenthesis?
Oh, what a happy little math question we have here! To solve arcsin(2/3), you simply take the inverse sine of 2/3, which is approximately 41.81 degrees. Remember, math is just like painting - take it one step at a time and enjoy the process of finding the answer.
What is the Inverse sin of 0.329?
arcsin(0.329) = 0.335 radians = 19.21 degrees
Is ascsin the same as sin-1?
Yes, both arcsin and sine inverse are the same.
How do you solve cot parenthesis inverse of sin 4 over 7 closed parenthesis?
The inverse sin function I write as arcsin x. Make use of the trignometric relationships: cos2θ + sin2θ = 1 ⇒ cosθ = √(1 - sin2θ) cotθ = cosθ/sinθ = √(1 - (sinθ)2)/sinθ sin(arcsin x) = x Then: cot(arcsin(x)) = √(1 - (sin(arcsin(x))2)/sin(arcsin(x)) = √(1 - x2)/x ⇒ cot(arcsin(4/7)) = √(1 - (4/7)2)/(4/7) = √(49/72 - 16/72) ÷ 4/7 = √(49 - 16) x 1/7 x 7/4 = 1/4 x √33
How do you solve for composite function?
That will depend on exactly how the equation is formed. In many cases, you can apply the inverse function to the outside first. Here is an example:sin(ln(x)) = ... To solve for "x", FIRST apply the inverse function of the sine (i.e., arcsin) to both sides of the equation. Next, apply the inverse of the natural logarithm to both sides. In this case, the exponential function (raise "e" to the power of the entire expression on both sides).
How do you solve cot parenthesis sin to the negative 1 parenthesis 2 over 3 closed parenthesis and another closed parenthesis?
I presume that sin-1x is being used to represent the inverse sin function (I prefer arcsin x to avoid possible confusion). Make use of the trignometirc relationships: cos2θ + sin2θ = 1 ⇒ cosθ = √(1 - sin2θ) cotθ = cosθ/sinθ = √(1 - sin2θ)/sinθ sin(arcsin x) = x Then: cot(arcsin(x)) = √(1 - sin2(arcsin(x))/sin(arcsin(x)) = √(1 - x2)/x ⇒ cot(arcsin(2/3)) = √(1 - (2/3)2)/(2/3) = √(9/32 - 4/32) ÷ 2/3 = √(9 - 4) x 1/3 x 3/2 = 1/2 x √5
How do you calculate arc sine?
arc sine is the inverse function of the sine function so if y = sin(x) then x = arcsin(y) where y belongs to [-pi/2, pi/2]. It can be calculated using the Taylor series given in the link below.
What is cot parenthesis sin to the negativde 1 parenthesis 2 over 3 closed parenthesis and another closed parenthesis?
If I read that correctly, you have: cot(sin-1(2/3)) which I understand to mean cot(arcsin(2/3)) which has the value 1/2 x √5 sin(arcsin(x)) = x cos2θ + sin2θ = 1 ⇒ cosθ = √(1 - sin2θ) cotθ = cosθ ÷ sinθ ⇒ cot(arcsin(2/3)) = cos(arcsin(2/3)) ÷ sin(arcsin(2/3) = √(1 - sin2(arcsin(2/3))) ÷ sin(arcsin(2/3) = √(1 - (2/3)2) ÷ (2/3) = 1/3 x √(9 - 4) x 3/2 = 1/2 x √5 As the reciprocal trignometric functions have separate names, eg 1/tan x = cot x, the use of the -1 "power" to indicate the inverse function is possible. However, to avoid any possible confusion, I prefer to use the arc- prefix to indicate the inverse function.
What trigonometric function gives the value of pi?
arcsin(1) arccos(0)
