yes
The [ 2x + 1 ] represents a function of 'y' .
a constant
No, this is not a function. The graph would have a vertical line at x=-14. Since there are more than one y value for every given x value, the equation does not represent a function. The slope of the equation also does not exist.
y = 4(2x) is an exponential function. Domain: (-∞, ∞) Range: (0, ∞) Horizontal asymptote: x-axis or y = 0 The graph cuts the y-axis at (0, 4)
x axis
If the question is, Is y = x4 an exponential function ? then the answer is no.An exponential function is one where the variable appears as an exponent.So, y = 4x is an exponential function.
f(x) = bX is not an exponential function so the question makes no sense.
Assuming that b > 0, it is an inverse power function or an inverse exponential function.
No, the equation y = 102x is not exponential. An exponential function is of the form y = a * b^x, where a and b are constants. In this case, the equation y = 102x is a linear function, as it represents a straight line with a slope of 102 and no exponential growth or decay.
No, the equation ( y = 1x ) is not an exponential function; it represents a linear function. In this equation, ( y ) is directly proportional to ( x ), resulting in a straight line when graphed. An exponential function typically has the form ( y = a \cdot b^x ), where ( b ) is a constant greater than zero and not equal to one.
True
equals(x,y)=1 if x=y =0 otherwise show that this function is primitive recursive
Direct
Yes.
The [ 2x + 1 ] represents a function of 'y' .
a constant
any number