The range of the arcsinx function is restricted because it is the inverse of a function that is not one-to-one, a characteristic usually required for a function to have an inverse. The reason for this exception in the case of the trigonometric functions is that if you take only a piece of the function, one that repeats through the period and is able to represent the function, then an inverse is obtainable. Only a section that is one-to-one is taken and then inverted. Because of this restriction, the range of the function is limited.
A function is normally expressed as y = f(x) where y represents the range of the function, and x refers to the domain. Consequently it is not clear what the question means.
A relationship is a function only if, for each value in the range there is at most one value in the domain which is mapped onto that value. Because of the periodicity of trigonometric functions, the range needs to be restricted. Restricting x to (-pi/2, pi/20) ensures that.
The sine function can take values in the interval [-1, 1] and so the domain, x, must be restricted to that interval because sine does not exist outside that interval.
O, of course.
The length of an arc equals he angle (in radians) times the radius. Divide the length by the radius, and that gives you the ange. Measure out the angle on a protractor and draw the length of the radius at the begining and end of the angle. Then draw theportion of the circle with its center at the location ofthe angle and extending out to the radius.
Any variables to help us out? What points are ABC? Why are there three points for a curved line (something that has two points)?
If you want to find the lenght of a curve y = f(x) between two values of x, lets say x1 and x2, you must compute this integral : Intx1 to x2[sqrt(dx2 + dy2)] You can either express the original function in terms of y or in terms of x, but it is much simpler to express it in a way such that the integral will not be improper. For example, lets say we want to find the lenght of arc of the curve y = x2 between x = 0 and x = 1. We could express this function in terms of y but we will keep it this way because if we change it, we will have to compute an improper integral, which can sometimes be very tedious. The differential of y = x2 is dy = 2x dx. We now need to square the differential : (dy)2 = (2x dx)2 = 4x2 (dx)2 We now have to compute this integral: Int0 to 1[sqrt(dx2 + dy2)] = Int0 to 1[sqrt(dx2 + 4x2 dx2)] = Int0 to 1[sqrt(1 + 4x2) dx] This last integral is easy to compute using a trigonometric substitution.
The integral from 0 to 2 pi of your constant value r will equal the circumference. This will be equal to 2*pi*r. This can be derived because of the following: Arc length = integral from a to b of sqrt(r^2-(dr/dtheta)^2) dtheta. By substituting the equation r = a constant c, dr/dtheta will equal 0, a will equal 0, and b will equal 2pi (the radians in a circle). By substitution, this becomes the integral from 0 to 2 pi of sqrt(c^2 + 0)dtheta, which leads us back to the original formula.
An arc-hyperbolic function is an inverse hyperbolic function.
1997-1998 season
Hormones have nothing to do in reflex arc.
It is probably arctan or arc tangent, the inverse of the tangent function.
The trigonometric function of an angle gives a certain value The arc trigonometric function of value is simply the angle For example, if sin (30 degrees) = 0.500 then arc sine ( 0.500) = 30 degrees
It is mathematically impossible to use arc length and an interval alone to determine a function!
what is the role of sensory and motor neurones in a reflex arc
Carpathian Mountains
It is just a name invented by mathematicians.
No, Redoubt Volcano is not part of an island arc. It is located in the Aleutian Range in Alaska and is associated with the Aleutian volcanic arc, which is a chain of volcanoes formed by the subduction of the Pacific Plate beneath the North American Plate.
Yes, it is called arcsin.