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The length of an arc equals he angle (in radians) times the radius. Divide the length by the radius, and that gives you the ange. Measure out the angle on a protractor and draw the length of the radius at the begining and end of the angle. Then draw theportion of the circle with its center at the location ofthe angle and extending out to the radius.
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How do you graph x2 plus y2 equals 9?
Draw a circle with its center at the origin and a radius of 3.
How can you tell by looking at a graph its a function?
Draw a graph of a given curve in the xoy plane. Now draw a vertical line so that it cuts the graph. If the vertical line cuts the graph in more than one ordinate then given graph is not a function. If it cuts the graph at a single ordinate such a graph is a function.(is called vertical line test)
How do you draw the cay?
go to google and type the cay ....... DUMB BUTTS
How do you graph Y equals 0.5x plus 1?
y = 0.5x + 1 x = -2, y = 0 x = -1, y = 0.5 x = 0, y = 1 x = 1, y = 1.5 x = 2, y = 2 Plot the points in the coordinate system, and draw the line, which is the line of the given equation.
What are the dimensions of an isosceles triangle of least area that can be circumscribed about a circle of radius r?
The isosceles triangle of least area that can be circumscribed about a circle of radius r turns out to be not just isosceles, but also equilateral. Each side has length 2r x ( 3 )0.5 . The area is r2 x (27)0.5 . Thanks are due to litotes for pointing out that the original answer did not actually answer the question ! tpm Since the equilateral triangle is also an isosceles triangle, we can say that at least area that can be circumscribed to a circle is the area of an equilateral triangle.If we are talking only for isosceles triangle where base has different length than two congruent sides, we can say that at least area circumscribed to a circle with radius r, is the area of an isosceles triangle whose base angles are very close to 60 degrees. Solution: Let say that the isosceles triangle ABC is circumscribed to a circle with radius r, where BA = BC. We know that the center of the circle inscribed to a triangle is the point of the intersection of the three angle bisectors of the triangle. Let draw these angle bisectors, and denote with D the point where the bisector drawn from the vertex, B, of the triangle, intersects the base AC. Since the triangle is an isosceles triangle, then BD bisects the base and it is perpendicular to the base. So that AD = DC, OD = r, and the triangles ADB and AOD are right triangles (O is the center of the circle). In the triangle ADB, we have:tan A = BD/AD, so that AD = BD/tan A In the triangle AOD, we have:tan A/2 = OD/AD, so that AD = r/tan A/2, and AC = 2r/tan A/2 Therefore,BD/tan A = r/tan A/2, andBD = (r tan A)/tan A/2 Area of triangle ABC = (1/2)(AC)(BD) = (1/2)(2r/ tan A/2)[(r tan A)/tan A/2] = (r2 tan A)/tan2 A/2 After we try different acute angles measure, we see that the smallest area would be: If the angle A= 60⁰,then the Area of the triangle ABC = r2 tan 60⁰/tan2 30⁰ ≈ 5.1961r2 If the angle A= 59.8⁰,then the Area of the triangle ABC = (r2 tan 59.8⁰)/tan2 29.9⁰ ≈ 5.1962r2
One radius of a circle is the same length as any other radius of any other radius?
The radius is the distance from the center of the circle to its edge. No matter how you draw this radius, it is one value of one length only, for any given circle.
Given radius and chord length. What is the height of arc to midpoint of chord?
Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).
How do you construct a triangle when the only measurements given are the length of the sides?
Draw a horizontal line AB equal to one of the side lengths. From A draw an arc of a circle of radius one of the remaining lengths. From B draw an arc of a circle of radius the third length. Where the arcs intersect is point C. Join AC and BC. Voila!
How do you draw the radius of a circle?
A line of any length may act as the radius of a circle. The radius is the distance from the centre to the perimeter of a circle.
How do you draw a chord when the perpendicular distance is given?
Using the fact that the centre of a chord is at right angles to the radius
Where do you find the radius?
A radius is the distance from the center point of a circle to the outside. To find the radius, you'd draw a line from the center of a circle straight out until it hits the circle itself, then measure the length of the line you just drew. If you are given a diagram where only the diameter is shown (the distance from one side of the circle to the other), just take half the diameter.
Is it possible to draw a circle of negative radius?
Radii are always positive. No, it is not possible to draw a circle with negative radius.
Draw a circle with radius 5 cmMark a point 'm' 13 cm away from the center Draw tangents to the circle from Mmeasure the length of the tangents and compare them?
They're equal, 12 cm long.
If you know the radius than how do you figure out the diameter?
.160 radius how do I draw it out.
What name is given to the line traced by a pair of compasses to form circle?
radius Additional answer Actually, the radius is the line that joins the centre to the circumference. The line that compasses draw to trace a circle is just that, a circle.
How do you use a straightedge and a compass to construct a triangle with 2 sides having the same length?
first draw your baseline, then set your compasses to say twice that length, then draw a circle of the same radius from each end of the baseline, use either intersection as the apex of your isosceles triangle.
How would you construct a right triangle given the length of a leg and the radius of the circumscribed circle?
To construct a right triangle given the radius of the circumscribed circle and the length of a leg, begin with two ideas. First, the diameter of the circle is equal to twice the radius. That's pretty easy. Second, the diameter of the circle is the length of the hypotenuse. The latter is a key to construction. Draw your circle, and draw in a diameter, which is the hypotenuse of the right triangle, as was stated. Now set you compass for the length of the leg of the triangle. With this set, place the point of the compass on one end of the diameter (the hypotenuse of your triangle), and draw an arc through the circumference of the circle. The point on the curve of the circle where the arc intersects it will be a vertex of your right triangle. All that remains is to add the two legs or sides of the triangle. Draw in line segments from each end of the hypotenuse (that diameter) to the point where your arc intersected the curve of the circle. You've constructed your right triangle. Note that any pair of lines that is drawn from the ends of the diameter of a circle to a point on the curve of the circle will create a right triangle.
