2(x + 3)(x + 1)
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(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)
(2x + 4)(2x - 4) to check your answer, use the FOIL method (first, outside, inside, last) F.... 2x x 2x = 4x^2 0.... 2x x -4 = -8x I..... 2x x 4 = 8x L.... 4 x -4 = -16 so 4x^2 - 16 = (2x + 4)(2x - 4)
8x + 6 = 2x + 24 To solve, collect like terms on each side; collect the x's on the left, the numbers on the right: 8X + 6 = 2x + 24 8x - 2x = 24 - 6 6x = 18 6x / 6 = 18 / 6 x = 3
8x - 22 = 2x + 28x - 2x - 22 = 2x - 2x + 26x - 22 = 26x - 22 + 22 = 2+ 226x = 24x = 24/6 = 4