2
(x - 5)(x - 3)
(4x - 1)(4x -1) or (4x - 1)2
Take out the common factor, 3: 3x + 6 = 3(x + 2).
If you say that something is "increased by a factor of 8," it just means it was multiplied by 8.
(4x + 1)(2x + 3)
(4x - 3)(2x + 3)
2(4x - 3)(x + 3)
8x squared
The answer is (2x^2+3)(4x+1)
8x^2 + 6x - 5 = 8x^2 + 10x - 4x - 5 = 2x * (4x + 5) - (4x + 5) = (2x -1) * (4x + 5)
(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
4x + 3 doesn't factor. It is in its simplest form.
(2x - 1)(4x + 1)
It is: 2(4x+5)
4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2
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