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What is the solution of this linear system 3x plus 5y equals -1 2x-5y equals 16?
3x + 5y = -1 2x - 5y = 16 Add the two equations: 5x = 15 or x = 3 Substitute for x in the first equation: 3*3 + 5y = -1 15 + 5y = -1 5y = -10 so y = -10/5 = -2 The solution is (x, y) = (3, -2)
How do you rewrite this equation so that y is a function of x -- 3x plus 5y equals 7?
Because of the limitations of the question software, it was not possible to determine what the original equation was supposed to be, so we assumed it is 3x + 5y = 7. It could have just as easily been 3x - 5y = 7, or even 3x/5y = 7.So, let's solve them all for x.3x + 5y = 73x = 7 - 5yx = (7 - 5y)/3How about 3x - 5y = 7?3x - 5y = 73x = 7 + 5yx = (7 + 5y)/3And 3x/5y = 7?3x/5y = 73x = 35yx = 35y/3 Solving for y The above equations wrote the equation so that x is a function of y, not the other way around. Here's how to rewrite the equation so that y is a function of x: 3x + 5y = 7 5y = -3x + 7 y = (-3x + 7)/5
How can you get coefficients that are equal for y. 3x plus 5y equals 7 2x plus 15y equals 11?
Multiply the first equation by 3 to give 9x + 15y = 21
What is 5y equals 9 plus 2y equals?
Solving for y: 5y = 9 + 2y 5y - 2y = 9 3y = 9 y = 9/3 = 3
What is the slope of 2x plus 5y equals 10?
To solve this, present the equation in the standard slope/intercept form of y = mx + c. 'm' is the slope. 2x + 5y = 10 5y = -2x + 10 y = -2/5x + 2 Therefore, -2/5 is the slope.
