x= Negative 4
technically it's already solved, you just have to graph it i guess.
x2 - 5x = 0Factor the left side:x (x - 5) = 0x = 0x = 5
Let's simplify: f(x) = 3x-3x, so f(x) =0, so y=0 The graph is a line along the x-axis.
so, if 2 minus Ln times 3 minus x equals 0, then 2 minus Ln times 3 equals x, therefore 2 minus Ln equals x divided by three, so Ln + X/3 = 2 therefore, (Ln + [X/3]) = 1
If x equals a constant number, the graph will be a vertical line. For example, the graph of x = 5 would be a vertical line that goes through the point (5,0). x equals 5 on every point along this lines.
2
-5, 5
X=27
a constant y=x-3 dy/dx=0 a straight line
0 5 /--------------/-----•------/
x=14
x = 13
The graph of x=5 is a vertical line on a set of coordinate axes that intercepts the x-axis at 5. Its slope is undefined.
x2-2x-10-5 = 0 x2-2x-15 = 0 (x+3)(x-5) = 0 x = -3 or x = 5
If: x-y = 4 and x-3y = 4 Then by solving the simultaneous equations: x = 4 and y = 0 So the lines intersect at (4, 0) which will be a vertical straight line
x2 - x = 20 x = 5