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Given:

2x - 3y = 2

3x + 2y = 3

Take the first equation, and solve for x:

x = (2 + 3y) / 2

Now plug it into the second equation:

∴ 3(2 + 3y) / 2 + 2y = 3

∴ 3 + 9y/2 + 2y = 3

∴ 9y/2 + 2y = 0

∴ 22y = 0

∴ y = 0

Then you can take that value of y, and plug it into either of our first equations to find x;

2x - 3y = 2

∴ 2x - 3(0) = 2

∴ 2x = 2

∴ x = 1

So x is equal to one, and y is equal to zero.

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