2x - 3y = 2
3x + 2y = 3
Simultaneous Equations.
Arbitrarily decide which letter to eliminate.
In this case 'y'.
To do this we bring the coefficients of 'y' to the same value. . To do this multiply the top equation by '2' and the bottom eq'n by.3.
Hence
4x - 6y = 4
9x + 6y = 9
We now add the two equations. The addition of '-6y + 6y = 0 ', So 'y' is eliminated.
Hence
13x = 13
x = 1
To find 'y' , we substitute 'x = 1' into either equation.
Hence
4(1) - 6y = 4
4 - 6y = 4
-6y = 0
y = 0
So the answer in ( x,y ) form is ( 1,0 ) .
4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
-2y = 10 2y = -10 y = -5
42+4y -12 = 13y -12 -2y 4y -13y+2y = 12 -12 -42 -7y = -42 y = 6
-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x
Solving for y: 5y = 9 + 2y 5y - 2y = 9 3y = 9 y = 9/3 = 3
2y = 4x + 4y = 2x + 2
you can not solve this equation
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
many solutions
2y + 4 = 3ySubtract 2y from both sides:4 = ywhew
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
3x+2y=6 2y=-3x+6 y=-1.5x+3
Subtract by 7x and divide by 2.
6x+2y=4 gives y=2-(1/3)x
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
You cannot solve one linear equation in two unknown variables.
80 = 3y + 2y + 4 + 1 75 = 5y 15 = y y = 15