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Given:
2x - 3y = 2
3x + 2y = 3
Take the first equation, and solve for x:
x = (2 + 3y) / 2
Now plug it into the second equation:
∴ 3(2 + 3y) / 2 + 2y = 3
∴ 3 + 9y/2 + 2y = 3
∴ 9y/2 + 2y = 0
∴ 22y = 0
∴ y = 0
Then you can take that value of y, and plug it into either of our first equations to find x;
2x - 3y = 2
∴ 2x - 3(0) = 2
∴ 2x = 2
∴ x = 1
So x is equal to one, and y is equal to zero.
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