Given:
2x - 3y = 2
3x + 2y = 3
Take the first equation, and solve for x:
x = (2 + 3y) / 2
Now plug it into the second equation:
∴ 3(2 + 3y) / 2 + 2y = 3
∴ 3 + 9y/2 + 2y = 3
∴ 9y/2 + 2y = 0
∴ 22y = 0
∴ y = 0
Then you can take that value of y, and plug it into either of our first equations to find x;
2x - 3y = 2
∴ 2x - 3(0) = 2
∴ 2x = 2
∴ x = 1
So x is equal to one, and y is equal to zero.
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4y = 2y + 40 4y - 2y = 2y -2y +40 2y = 40 y = 20 check 4(20) = 2(20) +40 80 = 80
-2y = 10 2y = -10 y = -5
42+4y -12 = 13y -12 -2y 4y -13y+2y = 12 -12 -42 -7y = -42 y = 6
-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8