3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
The equation can be simplified to show a value of Y in terms of X. 3X + 2Y +2 = 4Y + 4 3X + 2 = 2Y + 4 3X -2 = 2Y and 2Y = 3X - 2 means that Y = (3/2 X) -1
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
3x = 2y + 3 3x -3 = 2y +3 -3 3x - 3 = 2y (3x -3)/2 = 2y / 2 y = 1/2 x (3x - 3) 3x = 2y +3 3x - 3x = -3x +2y +3 0 = -3x +2y +3 -1 x (0) = -1 x (-3x +2y +3) 0 = 3x - 2y -3
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
3x+2y=6 2y=-3x+6 y=-1.5x+3
2y-3x=4
3x-2y=6 -2y=-3x+6 y=1.5x-3
-3x + 2y = 9 2y = 3x + 9y = 1,5x + 4,5
3x + 2y = 7
3x-2y = 5 -2y = -3x+5 y = 1.5x-2.5 in slope intercept form
y=16 x= -4
(2, -1)
4x-y=2, thereforey=4x-2sub y into 3x+2y=6...3x+8x-4=611x=10x=10/11
Standard form is: y = Mx + b so you must solve for y 3x = 2y + 7 3x - 7 = 2y 2y = 3x - 7 y = ( 3 / 2 )x - ( 7 / 2 )
x+2y-6=z -z -z x+2y-z-6=0 +6 +6 ---------> x+2y-z=6 3y-2z=7 ---------> 0x+3y-2z=7 4+3x=2y-5z -3x -3x ---------> -3x+2y-5z=4 Put them into a matrix, for x,y,z and their answers. Solve for [A]-1[B], and the answer comes to: x= 1.75, y= 1.5, and z= -1.25