y = 2 sin 3x
y' = 2(sin 3x)'(3x)'
y' = 2(cos 3x)(3)
y' = 6 cos 3x
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I'll show work. X2-8x-4=0. X2-8x=4. X-8x=2. -7x=2. X=-(2/7).
There are 2 unknowns
x3 -3x2 -x - 1 divided by x+2 equals x2-5x+9 remainder -19 It's difficult to show how to work it out on this computer but division with algebra has a lot in common with doing long division with integers.
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Υou show that it is continuous in every element of it's domain.