x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
5x + 32 = 11x - 105x - 11x = -10 - 32-6x = -42x = 7
If x equals 10 and y equals 10, then 9x plus 8y equals 170.
x2 +7x = 30 x2 +7x - 30 = 0 (x + 10)(x - 3) = 0 Now: x + 10 = 0 or x - 3 = 0 So: x = -10 or x = 3
I assume you mean...,X2 + 11X + 10(X + 1)(X + 10)==============factored
It doesn't factor evenly if it were x**2-11x+10: x**2-11x+10 = (x-1)(x-10)
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
x2 = 11x - 10 ∴ x2 - 11x + 10 = 0 ∴ (x - 10)(x - 1) = 0 ∴ x ∈ {1, 10}
To solve for x: x2 = 11x - 10 x2 - 11x = -10 x2 - 11x + 10 =0 (x - 1)(x - 10) = 0 x = {1, 10)
5x + 32 = 11x - 105x - 11x = -10 - 32-6x = -42x = 7
If 6x + 10 = 11x , then x=2.
The equation -30 times -10 plus 11X equals -29. This is a math problem.
(3r + 2)(r - 5)
-11x-1 = -10x-8 -11x+10 = -8+1 -1x = -7 x = 7
10 squared equals 100. 102 = 10*10 10*10 = 100
12x - 5 = 11x + 5(1) add 5 to both sides:12x - 5 + 5 = 11x + 5 + 512x = 11x + 10(2) next subtract 11x from both sides:12x - 11x = 11x - 11x + 10x = 10