Q: -30 x-10 plus 11x

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if f(x) = x3 + 4x2 - 11x - 30, then yes, (x - 3) is indeed a factor. f(x) = x3 + 4x2 - 11x - 30 ∴ f(x) = (x - 3)(x2 + 7x + 10) ∴ f(x) = (x - 3)(x + 2)(x + 5)

30 tens

6a -12b + 30 = 6 (a - 2b + 5)

4x+12-5x-30=-x-18

That totals 180.

Related questions

x+11x+30(x+5)(x+6)

x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6

The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.

There's a factor pair of 30 that adds up to 11. (x + 5)(x + 6)

66x^3 - 36x^2 = 6x^2(11x - 6) 55x - 30 = 5(11x - 6) 66x^3 - 36x^2 + 55x - 30 = (6x^2 + 5)(11x - 6)

The actual equation itself is the polynomial. There is no polynomial for it, and your question doesn't really make sense.

(x+5)(x+6) equals x^2 +11x+30

the answer is 300

-x^2 - 11x - 30 If you intended -1(x squared), making a quadratic equation, the solutions are -1 and +6.

It depends on what x is... You have to have either an x value or an answer to the equation. If x is 1, then it's 42. If x is 2, then it's 56.

x/6 + x/5 = 11 Multiply throughout by 30: 5x + 6x = 330 => 11x = 330 => x = 30

3 x10 30 x10