To factorize x^2 + 7x, we look for two numbers that multiply to the constant term (7) and add up to the coefficient of the x term (7). In this case, those numbers are 1 and 6. Therefore, we can rewrite the expression as x^2 + 1x + 6x + 6. Next, we factor by grouping: x(x + 1) + 6(x + 1). Finally, we factor out the common binomial factor of x + 6 to get (x + 1)(x + 6) as the fully factorized form.
(x + 11)(x - 4)
It is (x+3)(x+4) when factored
(x2 + 7x - 18) = (x + 9)(x - 2)
x2 +7x = 30 x2 +7x - 30 = 0 (x + 10)(x - 3) = 0 Now: x + 10 = 0 or x - 3 = 0 So: x = -10 or x = 3
49/4 or 12.25
X squared + 7X + 12?
7x-x2 = x(7-x)
x(x-7)
Factorise it: (x + 5)(3x - 8)
13X squared + 7X + 12
x^2+7x-30 = (x-3)(x+10)
(x + 11)(x - 4)
if its x(squared) its 7x(cubed) if its 2xX its 14x(squared)
(x + 2)(x + 1)
7x2+49x-42 = 7(x2+7x-6)
It is (x+5)(x+1) when factored
It is (x+6)(x+7) when factored