x2 + 7x + 6 = (x + 6) (x + 1)
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
x2 + 7x - 8 = (x + 8)(x - 1)
x^2+7x-30 = (x-3)(x+10)
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
x2+7x+12
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
x2 + 7x + 6 = (x + 6) (x + 1)
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
x2 + 7x - 8 = (x + 8)(x - 1)
x2+7x-8 = (x-1(x+8)
=3x * * * * * The correct answer is: x2 + 7x + 12 = (x + 3)(x + 4).
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
i got 42 divided 7x
x2-7x+12 (x-3)(x-4)
1