0
y^(2) + 9y - 52 #
Write down all the factors of '52'
Hence
1, 52 ; 2 , 26 ; 4 , 13 ;
By addition or subtraction, select a pair of factors that 'add' to '9'
They are, '4' & '13' ; Hence 13 - 4 = 9
Set up ther brackets , without the signs
Hence
( y 4)(y 13)
Since '52' is negative (-) , then the two signs are different.
Since '9' is positive then the larger factor is positive(+).
Hence inserting
(y - 4)(y + 13)
Factored!!!!
Done!!!!
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What are points of intersection of the line 3x -y equals 5 with the curve of 2x squared plus y squared equals 129?
Straight line: 3x-y = 5 Curved parabola: 2x^2 +y^2 = 129 Points of intersection works out as: (52/11, 101/11) and (-2, -11)
X 2 plus y 2 - 10x plus 4y - 52 equals 0?
x2 + y2 - 10x + 4y - 52 = 0 x2 - 10x + y2 + 4y = 52 Complete the square (x2 - 10x + 25) + (y2 + 4y + 4) = 52 + 25 + 4 (x - 5)2 + (y + 2)2 = 81 (x - 5)2 + (y - -2)2 = 92 This is the equation of a circle with center (5, -2), and radius 9.
What is the largest integer value of x given that -52x is less than or equal to 7?
-52x <= 7 (-52x)/(-52) >= 7/(-52) {divide both sides by -52, and reverse the inequality when dividing by a negative. x >= -7/52 There is no largest integer value for x. If the question was ... greater than or equal to ... then the solution would be x <= -7/52, and the largest integer value would be -1.
How many weeks in 2003?
52
What are the solutions to the simultaneous equations of 3x -y equals 5 and 2x2 plus y2 equals 129?
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
