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There are three main types of vertices for an absolute value function. There are some vertices which are carried over from the function, and taking its absolute value makes no difference. For example, the vertex of the parabola y = 3*x^2 + 15 is not affected by taking absolute values.
Then there are some vertices which are reflected in the x-axis because of the absolute value. For example, the vertex of the absolute value of y = 3*x^2 - 15, that is y = |3*x^2 - 15| will be the reflection of the vertex of the original.
Finally there are points where the function is "bounced" off the x-axis. These points can be identified by solving for the roots of the original equation.
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The above answer considers the absolute value of a parabola. There is a simpler, more common function, y = lxl. In this form, the vertex is (0,0).
A more general form is y = lx-hl +k, where y = lxl has been translated h units to the right and k units up. This function has its vertex at (h,k).
Finally, for y = albx-hl + k, where the graph has been stretched vertically by a factor of a and compressed horizontally by a factor of b, the vertex will be at (h/b,ak).
Of course, you can always find the vertex by graphing, especially since you might not remember the 2nd or 3rd parts above.
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How do you find critical value for a total revenue function?
If it is a differentiable function, you find the value at which its derivative is 0. But in general, you can plot it as a line graph and see where it peaks.
How do you find the domain and range of the function f of x equals half of the absolute value of x minus 2?
The domain could be the real numbers, in which case, the range would be the non-negative real numbers.
What is x to the second power minus x?
A function--namely a parabola (concave up). To "evaluate" this function you would need an x value and would find the resulting y value. To "solve" this function, you would probably be given a y value and asked to find the corresponding x value(s).
Limits in calculus?
A limit in calculus is a value which a function, f(x), approaches at particular value of x. They can be used to find asymptotes, or boundaries, of a function or to find where a graph is going in ambiguous areas such as asymptotes, discontinuities, or at infinity. There are many different ways to find a limit, all depending on the particular function. If the function exists and is continuous at the value of x, then the corresponding y value, or f (x), is the limit at that value of x. However, if the function does not exist at that value of x, as happens in some trigonometric and rational functions, a number of calculus "tricks" can be applied: such as L'Hopital's Rule or cancelling out a common factor.
What is the vertex of the graph of the function y equals x2-4x plus 3?
To find the extreme value of the parabola y = x2 - 4x + 3 ...(1) Take the derivative of the equation.y = x2 - 4x + 3y' = 2x - 4(2) Set the derivative = 0 and solve for x.y' = 2x - 40 = 2x - 42x = 4x = 4/2x = 2(3) Plug this x value back into the original equation to find the associated y coordinate.x = 2y = x2 - 4x + 3y = (2)2 - 4(2) + 3y = 4 - 8 + 3y = -1So the vertex is at (2, -1).
Where do you find the absolute value function on TI-89 titanium calculator?
There
How can I find the absolute value of -3.2?
To find the absolute value of -3.2, you simply ignore the negative sign and take the positive value of the number. In this case, the absolute value of -3.2 is 3.2. The absolute value function essentially measures the distance of a number from zero on the number line, disregarding its direction.
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.
How do you find the vertex of the parabola y equals -4x2 - 16x - 11?
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
How do you find the domain and range of an absolute value function?
The domain would always be the set of all real numbers while the range depends on the sign outside the term in the absolute value and the other operations to be evaluated outside the absolute value term.
What does it to find the absolute value of a number?
to find the absolute value u see how far it is from 0 and the absolute value is always positive
How do you find the absolute value of 1.5?
To find the absolute value of 1.5, you simply ignore the negative sign, if any, and take the positive value. Since 1.5 is already a positive number, its absolute value is 1.5. The absolute value function essentially returns the distance of a number from zero on the number line, regardless of its sign.
Find the Absolute Value -1294?
Absolute Value -1294 is 1294.
Find the absolute value of 5?
The absolute value of 5 is 5.
Find the absolute value -9?
Absolute value of -9 is 9.
Find the absolute value of -41?
Absolute value of -41 is 41.
Find the absolute value of -28?
absolute value of - 28 = 28
