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To find the extreme value of the parabola y = x2 - 4x + 3 ...
(1) Take the derivative of the equation.
y = x2 - 4x + 3
y' = 2x - 4
(2) Set the derivative = 0 and solve for x.
y' = 2x - 4
0 = 2x - 4
2x = 4
x = 4/2
x = 2
(3) Plug this x value back into the original equation to find the associated y coordinate.
x = 2
y = x2 - 4x + 3
y = (2)2 - 4(2) + 3
y = 4 - 8 + 3
y = -1
So the vertex is at (2, -1).
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Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals". There is no symbol before 4x.
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