I guess you mean an equation written in function notation, for example:
f(x) = 3x + 2
For the purposes of doing math, it may help to think of this as an alternative way of writing, for example (using the function above):
y = 3x + 2
It isn't clear from the question what you want to "solve", but if you write the equation this way, it might become a bit less confusing.
In its normal form, you do not solve differential equation for x, but for a function of x, usually denoted by y = f(x).
Put f(x) = 0 and solve for x.
Solve f(x) =0 or y = 0 (depending on how the equation is given).
To solve the equation f(x) = 2x-5, set f(x) equal to zero and solve for x. In this case, you have 2x-5 = 0. Add 5 to both sides of the equation to isolate the x term, giving you 2x = 5. Finally, divide both sides by 2 to solve for x, which gives x = 5/2 or x = 2.5.
f(x) = x2 + 5x + 1 The roots of this equation are x = -0.2087 and x = -4.7913 (approx).
The solution to the equation y = 1/2x will be x= 2y.
Solve the equation for x, and enter your answer in the box below.
When we solve an equation in mathematics we say that we find its root. Let f(x) = 0 be an equation. A root of the equation is a value k such that f(k) = 0. If f(x) is a polynomial, then f(x) = 0 is a polynomial equation. By the Factor Theorem, k is a root of this equation if and only if (x - k) is a factor of f(x). If (x - k) is a factor of f(x), then k is a simple root. If (x - k)^2 is a factor of f(x), then k is a double root. If (x - k)^3 is a factor of f(x), then k is a triple root, and so on. Thus, we can say that a root of order n, where n = 2 or n > 2, is a multiple (or repeated) root.
In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.
You need not have x in an algebraic equation. You solve whichever one is the easiest and that depends on the set of equations that you have.
Set up the equation and solve: x + 5 = -13 (next subtract 5 from each side of the equation to solve for x) x = -18
The quadratic formula cannot be used to solve an equation if the coefficient of the equation x square term is what?