I guess you mean an equation written in function notation, for example:
f(x) = 3x + 2
For the purposes of doing math, it may help to think of this as an alternative way of writing, for example (using the function above):
y = 3x + 2
It isn't clear from the question what you want to "solve", but if you write the equation this way, it might become a bit less confusing.
In its normal form, you do not solve differential equation for x, but for a function of x, usually denoted by y = f(x).
Put f(x) = 0 and solve for x.
Solve f(x) =0 or y = 0 (depending on how the equation is given).
To solve the equation f(x) = 2x-5, set f(x) equal to zero and solve for x. In this case, you have 2x-5 = 0. Add 5 to both sides of the equation to isolate the x term, giving you 2x = 5. Finally, divide both sides by 2 to solve for x, which gives x = 5/2 or x = 2.5.
f(x) = x2 + 5x + 1 The roots of this equation are x = -0.2087 and x = -4.7913 (approx).
The solution to the equation y = 1/2x will be x= 2y.
Solve the equation for x, and enter your answer in the box below.
When we solve an equation in mathematics we say that we find its root. Let f(x) = 0 be an equation. A root of the equation is a value k such that f(k) = 0. If f(x) is a polynomial, then f(x) = 0 is a polynomial equation. By the Factor Theorem, k is a root of this equation if and only if (x - k) is a factor of f(x). If (x - k) is a factor of f(x), then k is a simple root. If (x - k)^2 is a factor of f(x), then k is a double root. If (x - k)^3 is a factor of f(x), then k is a triple root, and so on. Thus, we can say that a root of order n, where n = 2 or n > 2, is a multiple (or repeated) root.
In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.
Set up the equation and solve: x + 5 = -13 (next subtract 5 from each side of the equation to solve for x) x = -18
You need not have x in an algebraic equation. You solve whichever one is the easiest and that depends on the set of equations that you have.
The quadratic formula cannot be used to solve an equation if the coefficient of the equation x square term is what?