The [ 2x + 1 ] represents a function of 'y' .
y=2x+4 --> x=2y+4 ==> y=(x-4)/2
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y = -x2 + 1 This function describes a parabola that opens downward. To find the top of it's range, you need to find it's focal point. You can do that very easily by taking the derivative of the equation and solving it for 0: y = -x2 + 1 ∴ y' = -2x let y' = 0: 0 = -2x ∴ x = 0 Now you can calculate the y value at that point: y = -02 + 1 ∴ y = 1 So that function describes an upside down parabola whose peak is at the point {0, 1}. It's range then is: {y | y ∈ ℜ, y ≤ 1}
y=f(x)= x(2x+y)=7 f(x)=2x^2 +xy -7 = 0 y=2x^2 +xy -7 y-xy -7 + 2x^2 = 0 y(1-x)=2x^2-7 y=(2x^2-7) / (1-x) Excuse the working. Y equals 2 X squared minus 7 all divided by 1-X
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The [ 2x + 1 ] represents a function of 'y' .
Y = 2X + 8 is a linear function of the form, Y = mX + c. A line.
Solve for y.2x+y=5*subtract 2x from both sides*2x+y-2x=5-2xy=-2x+5 / y=5-2x
y = f(x) = (2x + 1)/(x - 1)y*(x - 1) = (2x + 1) xy - y = 2x + 1xy - 2x = y + 1x(y - 2) = y + 1so x = (y + 1)/(y - 2) assuming y�2.So the inverse function is f-1(x) = (x + 1)/(x - 2)
2x+y=0To find standard from slope/intercept, all you have to do is move the x term over by doing its opposite sign. So y=2x+0 would be -2x+y=0y=-2x+0 (The absence of b, or y intercept indicates the function goes through the origin)
If you have a function, such as y=2x also written as f(x)=2x, then you plug in the number. So for example if x=1 then you have y=2 or f(1)=2.
To find the inverse of a function, you replace x with y and y with x. Here, y=2x-4 would become x=2y-4. Now, we solve for y. 2y=x+4. y=(x/2)+4, and that is the inverse equation.
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The rate of change for the linear (not liner) function, y = 2x +/- 3 is 2.
If Y equals 2X - 2X - 24, then there is one root, and it is -24. The two 2X's cancel each other out.
If you mean: y = -2x-3 then the slope is -2 and the y intercept is -3