you can add logarithms if they both have the same base
use this rule if they both have the same base, a:
logam+logan= loga(mxn)
all you have to do is multiply the base numerals together (mxn) :)
ln5+2ln6
= loge(5)+2loge(6)
simplify it using
nlogam= logam^n
= loge(5)+loge(6)^2
= loge(5)+loge(36)
use the first rule at the very top
= loge(5x36)
=loge(180)
y = 5xy' = 5xln5 = ln5(5x)y" = ln5(5xln5) = (ln5)25x = 2.59(5x)
Use natural logs. 5^(8-2X) = 25 ln5^(8-2X) = ln25 8-2X ln5 = ln25 8-2X = ln25/ln5 8-2X = 2 subtract 8 from each side -2X = -6 divide each side by -2 X = 3 check 5^(8-3(2)) = 25 5^2 = 25 25 = 25 checks
5^X = 11 ln(5^X) = ln11 Xln5 = ln11 X = ln11/ln5 = 1.48989
Exponential form is ax = b. Logarithmic form is logab = x. For example, 102 = 100 is the same as log10100 = 2. Another example: 53 = 125 is the same as log5125 = 3. If there is no number under the log (for example, log3), the the number is understood to be ten. For example, log8 is the same as log108. A natural log uses the symbol ln. In this case, the number is understood to be e (which equals about 2.718). For example, ln5 is the same as loge5 (which the same as log2.7185).
it's an expression, so you'll have to use a calculator.=========================Right! In this day and age, we've finally reached the point where nobodyknows how to do squat without his machines. Plus ... nobody has a cluewhether the machine has given him the right answer. Beautiful!ln(5) - 3 ln(2) =ln(5) - ln(23) =ln (5/23) = ln (5/8).Note:That's not the 'solution' to anything. It's just a different, neater way of writingthe original expression that's in the question. In an algebra class, the answerdoesn't matter. All they really want is for you to learn how to get this far, andno calculator will tell you that it's ln(5/8).If your class is so regimented that you need the numerical answer, then you cango ahead and use the calculator for that:ln (5/8 ) = -0.47 (rounded)
There have been several past Pokemon events in the UK: - Aurora Ticket giveaway (used to reach Buirth Island, where Deoxys is) at Vue cinemas in October - November 2005 (for Pokemon Fire Red & Leaf Green) - Mew giveaway at Toys R Us in August 2007 (for Pokemon Emerald) - Darkrai giveaway at Woolworths stores in August 2008 (for Pokemon Diamond & Pearl) - Riolu, Manaphy, and Darkrai missions for Pokemon Ranger: Shadows of Almia available for download over Nintendo WiFi in November 2008 - February 2009 (allow you to transfer a Riolu or Manaphy to Pokemon Diamond or Pearl) - Darkrai mission for Pokemon Ranger: Shadows of Almia available for download over Nintendo WiFi in December 2008 - January 2009 (allows you to transfer a Darkrai to Pokemon Diamond or Pearl) - Shaymin mission for Pokemon Ranger: Shadows of Almia available for download over Nintendo WiFi in March 2009 (does NOT allow you to obtain a Shaymin) - Shaymin giveaway at GAME stores in April 2009 (for Pokemon Diamond & Pearl) There are also 2 more downloadable missions for Pokemon Ranger: Shadows of Almia, which feature Dialga and Palkia. As far as I know, these are still available for download over Nintendo WiFi. Like the Shaymin mission, you will not get a Dialga or Palkia if you complete these missions; they are just missions which feature these Pokemon. So far, there have been no announcement of any future UK events.
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