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Earn +20 ptsQ: How do you solve 2x2 plus 1x-3 equals 0?
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What are the solutions to the simultaneous equations of 3x -y equals 5 and 2x2 plus y2 equals 129?
The solutions work out as: x = 52/11, y = 101/11 and x = -2, y = -11
Which is a solution to 2x2 - 7x plus 3 equals 0?
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
How do you find the x- coordinates of the turning points of y equals x3-2x2-5x plus 6?
Differentiate the function with respect to x: d/dx (x3 - 2x2 - 5x + 6) = 3x2 - 4x - 5 Set this derivative = 0 and solve. 3x2 - 4x - 5 = 0 implies that x = -0.7863 or 2.1196 (to 4 dp)
Solve 2x squared - 6x plus 4 equals 0?
2x2 - 6x + 4 = 0 2(x2 - 3x + 2) = 0 2(x - 1)(x - 2) = 0 x - 1 = 0 and x - 2 = 0 So, x = 1 and x = 2.
How do you solve 2x squared minus five equals zero?
2x2-5 = 0 +5 +5 2x2 = 5 /2 /2 x2 = 5/2 sqrt(x2) = sqrt (5/2) x = sqrt(5/2) Ps: Sqrt means square root
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