4x+3y-2x+y 4x-2x+3y+y 2x+4y Taking out 2 common 2(x+2y) Hence the required answer is 2(x+2y)
Solve for Y algebraically. 4X + 8Y = 16 8Y = - 4X + 16 Y = - 1/2X + 2 graph and see that the Y intercept = 2
2x + 5 = 7 - 4x ie 2x + 4x = 7 - 5 ie 6x = 2 x = one third.
2(2x + 3)
To find the extreme value of the parabola y = x2 - 4x + 3 ...(1) Take the derivative of the equation.y = x2 - 4x + 3y' = 2x - 4(2) Set the derivative = 0 and solve for x.y' = 2x - 40 = 2x - 42x = 4x = 4/2x = 2(3) Plug this x value back into the original equation to find the associated y coordinate.x = 2y = x2 - 4x + 3y = (2)2 - 4(2) + 3y = 4 - 8 + 3y = -1So the vertex is at (2, -1).
4x+2=2x-102x=-12 x=-6
2y = 4x + 4y = 2x + 2
-2x = -4x + 24 -2x + 4x = 24 2x = 24 x = 24/2 x = 12
4x + 2 + 2x - 2x = 14 4x = 14 - 2 4x = 12 x = 3
If you mean integral[(2x^2 +4x -3)(x+2)], then multiply them out to get: Integral[2x^3+8x^2+5x-6]. This is then easy to solve and is = 2/4x^4+8/3x^3+5/2x^2-6x +c
(2x - 3)(4x + 9)(2x + 3) = (2x - 3)(2x + 3)(4x + 9) = [(2x)^2 - (3^2)](4x + 9) = (4x^2 - 9)(4x + 9) = (4x^2)(4x) + (4x^2)(9) - (9)(4x) - (9)(9) = 16x^3 + 36 x^2 - 36x - 81
2 - 4x - 2x + 4 = 6 - 6x
Simplify 4x + 3 = 2x + 8 2x = 5 x =2½
2x + 2 = 4x -1 2x = 3 x = 1.5
2x = 4x +1 2x-4x = 1 -2x = 1 x = - 1/2 check Leftside = 2 (- 1/2) = -1 Right side = 4 (- 1/2) +1 = -2 + 1 = 1 - 2 = -1 LS = RS therefore x = - 1/2
-2x + 6 <= 4x + 18 -2x <= 4x + 12 -12 <= 6x -2 <= x
2x+2=161-4x 6x+2=161 6x=159 x=26.5 See that? Add 4x to the other side, Subtract 2 from the other side, divide 159 by 6. Done.