x = 64
64 + 64 = 128
find x when, 2x=128 2x=128 /2 /2 x=128 /2 x=64 then check your answer by doing the following if x=64, then what is 2x? 2(64)=? or 2 * 64=? or 2 x 64=? 2 times 64 equals 128!
8-3x = 128 -3x = 128-8 -3x = 120 x = -40
x = 13
it equals x1 it equals x1
60
What is 'what'???? You write it as 'unknown' or 'x' . Hence 50 + x = 128 Subtract '50' from both sides x = 78 The Answer!!!!!! (The 'What???').
To solve x + x + x + x, set the problem up as multiplication like this 4x = 128. Divide both sides of the problem by 4. You will get x = 32. To check your work, substitute 32 for the x and do the math. 4 x 32 = ?. If the answer is 128, the answer is correct.
2048
find x when, 2x=128 2x=128 /2 /2 x=128 /2 x=64 then check your answer by doing the following if x=64, then what is 2x? 2(64)=? or 2 * 64=? or 2 x 64=? 2 times 64 equals 128!
128 x 4 = 512
8 x 8 x 8 x 8 = 8^(4) = 64^(2) = 4096
545
The answer is 545
25.6 x 5 = 128
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
1 x 128, 2 x 64, 4 x 32, 8 x 16.
Well to start 1 times any number is itself. So 1 x 128 is 128. 4 x 32 is 128.