0
128 = x7 (we see that x > 0, since x is raised to an odd power)
27 = x7 (this is true only when x = 2)
2 = x
Remember that a logarithm is an exponent.
The statement 128 = x7 is equivalent to logx 128 = 7.
logx 128 = 7
log 128/log x = 7 (or reverse the both sides)
log x/log 128 = 1/7 (multiply by log 128 to both sides)
log x = log128/7 (or use base 10 for the logarithm)
log10 x = log128/7 (write the equivalent statement)
10log 128/7 = x
2 = x
or use the natural log, ln.
128 = x7
ln 128 = ln x7
ln 128 = 7ln x
(ln 128)/7 = ln x
e(ln128)/7 = elnx (elnx = x )
2 = x
What else can I help you with?
How do you solve 8-3x equals 128?
8-3x = 128 -3x = 128-8 -3x = 120 x = -40
What does x equals when 2x equals 128?
find x when, 2x=128 2x=128 /2 /2 x=128 /2 x=64 then check your answer by doing the following if x=64, then what is 2x? 2(64)=? or 2 * 64=? or 2 x 64=? 2 times 64 equals 128!
What is the answer for x plus x equals 128?
x = 64 64 + 64 = 128
Can you show me the work on how to solve 16x2 - 24x plus 7 equals 0?
Straight to the quadratic equation. -b +/- sqrt(b^2 - 4ac)/2a 16 = a -24 = b 7 = c 24 +/- sqrt[ (-24)^2 - 4(16)(7)]/2(16) 24 +/-sqrt( 576-448)/32 24 +/- sqrt(128)/32 ( reduce fraction ) 3 +/- sqrt(128)/4 ( let us see about that mess under the radical )( like this!) 3 +/- sqrt( 4^2 * 2^2 * 2)/4 (4 and 2 come out and make 8) 3 +/- 8sqrt(2)/4 ( you finish)
How do you find the equation of a parabola in standard form with x intercepts at -2 and 6 passing through 1 and 8?
Since we know the intercepts, its best to solve the general form first and then convert to the standard form. The intercepts tell us that for some constant, a y=a*(x+2)(x-6) We also know that the parabola must run through a given point (1,8) so we can plug that value in to get our value of a 8=a*(3)(-5) a=-8/15 Next, expand the formula and start moving numbers around until you are in standard form y=-8/15*(x²-4x-12) y=-8/15*((x-2)²-16) y=-8/15*(x-2)²+128/15
What to the power of 2 equals 128?
The number that, when raised to the power of 2, equals 128 is the square root of 128. The square root of 128 is approximately 11.31. Therefore, 11.31 raised to the power of 2 equals 128.
What to the seventh power equals 128?
It is: 2 to the power of 7 = 128
How do you solve 8-3x equals 128?
8-3x = 128 -3x = 128-8 -3x = 120 x = -40
What equals 2 to the 7th power?
2 to the 7th power equals 128....
Solve for x 5x equals -123?
128
What does 2 to the 7 power equal?
27 equals 128
What number to the seventh power equals 128?
Two.Two.Two.Two.
What is 8x8x8x8 equals?
128
What is the seventh root of 128?
The seventh root of a number is the number that, when raised to the power of 7, equals the original number. To find the seventh root of 128, you would calculate 128^(1/7), which is approximately 2.0801. This means that 2.0801 raised to the power of 7 is equal to 128.
What is 128 as a power of 2?
Well, isn't that a happy little question! 128 can be written as a power of 2 by seeing how many times you can divide 128 by 2 until you reach 1. In this case, you can divide 128 by 2 six times to get 2^7, which equals 128. Keep exploring those numbers and you'll create a beautiful mathematical landscape!
128 oz equals how many lb?
128 oz equals 8 pounds.
How do you solve x plus x plus x plus x equals 128?
To solve x + x + x + x, set the problem up as multiplication like this 4x = 128. Divide both sides of the problem by 4. You will get x = 32. To check your work, substitute 32 for the x and do the math. 4 x 32 = ?. If the answer is 128, the answer is correct.
