First, take the inverse sine of both sides of the equation.
That gives you x = sin-1(6), which is sadly undefined...in reality, but who needs that!
It can be proven that sin-1(x) = -i*log[i*x + √(1-x2)]
So in this case:
= -i*log[i*6 + √(1-36)] = -i*log[6*i + √(-35)]
= -i*log(11.916*i)
= 1.57 - 2.48*i
X is 6
It equals -36. To solve replace x with -6, because it is the value given in the problem and then just multiply. 6(-6)= -36.
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
Sin[x] = Cos[x] + (1/3)
sec x - cos x = (sin x)(tan x) 1/cos x - cos x = Cofunction Identity, sec x = 1/cos x. (1-cos^2 x)/cos x = Subtract the fractions. (sin^2 x)/cos x = Pythagorean Identity, 1-cos^2 x = sin^2 x. sin x (sin x)/(cos x) = Factor out sin x. (sin x)(tan x) = (sin x)(tan x) Cofunction Identity, (sin x)/(cos x) = tan x.
2 sin2 x + sin x = 1. Letting s = sin x, we have: 2s2 + s - 1 = (2s - 1)(s + 1) = 0; whence, sin x = ½ or -1, and x = 30° or 150° or 270°. Or, if you prefer, x = π/6 or 5π/6 or 3π/2.
sin7x-sin6x+sin5x
X is 6
There is nothing to solve in this equation because there is no =. If you accidentally omitted what the expression equals then resubmit it and I'll be happy to look at it
x=6
6
-6 = x + 6 Solve for x -6 - 6 = x x = -12
x = 1/3
Cos x = 1 / Sec x so 1 / Cos x = Sec x Then Tan x = Sin x / Cos x = Sin x * (1 / Cos x) = Sin x * Sec x
-4
X = 1.8
x=4 x=4